Question

The length of a rectangle is 15ft greater than the width. The area is 100 square ft. Find the length and the Width.​

Answer 1

Step-by-step explanation:

so let's say that the width is x then the length is x+15

and the area of a square is length times width

x(x+15)=100

x^2+15x-100=0

(x+20)(x-5)=0

x=5 or x=-20 but a side length can't be negative so x would equal 5

Length=x+15 with 5 as x

Length=20

Width=5

Hope that helps :)

Answer 2

Answer:

Let the Width be x then ATQ ,length would be x+15

Area of a Rectangle

$length \times width$

Step-by-step explanation:

$(x + 15) \times x = 100 \\ x {}^{2} + 15x = 100 \\ x {}^{2} + 15x - 100 = 0 \\ x {}^{2} + 20x - 5x - 100 = 0 \\ x(x + 20) - 5x(x + 20) \\ (x - 5)(x + 20) \\ so...... \\ x = 5 \:$

x = 5=> Width

x +15 = 20=> Length