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2 years ago

6

A group of friends were working on a student film that had a budget of $900 they use 87% of their budget on costumes how much mo

ney did they spend on costumes

1 answer:

sergey [27]2 years ago

8 0

To find the answer use multiplication. 87% as a decimal equals 0.87 (87 divided by 100). Then multiply 0.87 by 900. Your answer should be $783.

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Jayla had 4 chocolate chip cookies and 3 sugar cookies. Her sister ate two of her chocolate chip cookies. What fraction of cooki

Ahat [919]

The starting fraction is 7/7
now you subtract 2 for the 2 cookies eaten
7/7 - 2/7 = 5/7
your end fraction is 5/7

4 0

3 years ago

sum_(n=0)^infinity (x+8)**n/(3**n) (a) Find the values of x for which the series converges. (Enter the smaller number first.) (

Fed [463]

Idk but probably the sum is 6367337282&363632$3!.??.):

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3 years ago

If a plate is moving 3.3 cm/yr, what distance [in kilometers (km)] will the plate move in 1 million years?

sasho [114]

$\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}$

<h2>33 km</h2>

3.3cm = 0.000033km (divide by 100,000.

So, 0.000033km/yr.

0.000033 × 1,000,000

=33km

Thanks
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3 0

2 years ago

Kumar bought some mangoes. The price of each mango () is found to be 6 more than the total number of mangoes bought by him and t

spayn [35]

Answer:

Price = 20, Amount = 14

Step-by-step explanation:

A = Amount of Mangoes

P = Price for 1 Mango

P = A + 6

280 = P * A

insert A+6 for P

280 = (A+6) * A

280 = 6A + A²

280=1*a^2+6*a | Vertausche beide Seiten der Gleichung.

1*a^2+6*a=280 | quadratische Ergänzung: ergänze auf beiden Seiten (3)^2

1*a^2+6*a+(3)^2=3^2+280 | Rechne 3 hoch 2 aus.

1*a^2+6*a+(3)^2=9+280 | addiere 9 und 280

1*a^2+6*a+(3)^2=9+280 | Fasse die rechte Seite mit Hilfe der binomischen Formel zusammen.

1*(1*a+(3))^2=289 | Auf beiden Seiten Quadratwurzel ziehen.

1*a+(3)=+-*289^0.5

1*a_1+(3)=289^0.5

1*a_1+3=289^0.5 | Ziehe die Wurzel aus 289

1*a_1+3=17 | -3

1*a_1=14

8 0

2 years ago

Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company

erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that $n = 16$

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that $p = 0.5$

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0$

$P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002$

$P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018$

$P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105$

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

6 0

2 years ago