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2 years ago

10. The translation (x, y) = (x + 10, y-6) is applied to ABC to create a new image A'B'C'. Graph

Mathematics

1 answer:

yulyashka [42]2 years ago

3 0

Answer:

here you go mate.

These are the solutions

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1. Solve x2-4x+18=0.

Naya [18.7K]

X²-4x+18=0

x= 4 ± √(16-4*1*18) / 2

x=4±√(16-72) /2

x= 4 ± √-56 /2

x = 4±2i√14 / 2

x= 2±√14 * i

8 0

3 years ago

Read 2 more answers

Select all the expressions that are greater than 1.

natita [175]

Select the following expressions. I will just list the letter choice:

A, C, D

3 0

3 years ago

I hope that we pass this semester god bless :)) calming it

Umnica [9.8K]

Answer:

me too

Step-by-step explanation:

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2 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$