Here are the numbers that represent each based on the box plot:
Median: 11 (located at the vertical line in the middle of the box)
Range: 19 - 7 = 12 (highest value - lowest value)
25%: 9 (at the left end of the box)
75%: 14 (at the right end of the box)
Interquartile range: 14 - 9 = 5 (the distance from the beginning to the end of the middle half of the data)
Answer:
Option A) 32
Step-by-step explanation:
Given the quadratic function, g(x) = x²- 5x + 8:
In order to evaluate and determine the output value given g(8), substitute the input value into the function:
g(x) = x²- 5x + 8
g(8) = (8)²- 5(8) + 8
g(8) = 64 - 40 + 8
g(8) = 32
Therefore, the correct answer is Option A) 32.
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
15,000 liters
Step-by-step explanation:
First, find the volume in meters. 5*3*1=15 meters
1 meter = 1000 liters
(x15)
15 meters = 15000 liters
Hope this helped :D
