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3 years ago

A sequence starts 0, 5, ...

Mathematics

1 answer:

kap26 [50]3 years ago

5 0

Answer:

0, 5, 10, 15, 20

0, 5, 40, 405, 5,120

Step-by-step explanation:

One rule can be "add 5 to the previous term to get the next term."

0, 5, 10, 15, 20

Second rule:

For each term number 1, 2, 3, ..., n,

each term = 5(n - 1)^n

0, 5, 40, 405, 5,120

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Read 2 more answers

If ORBIT is coded BEOVG, then how is PLANET coded? /

arlik [135]

Answer:

1. CYNARG

Step-by-step explanation:

This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

$C = (P + o) \text{mod} 26$

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so $P = 15$ .

B is the 2nd letter in the alphabet, so $C = 2$

$C = (P + o) \text{mod} 26$

$2 = (15 + o) \text{mod} 26$

$|o = |2-15| \text{mod} 26$

$o = 13$

$C = (P + 13) \text{mod} 26$

PLANET:

P is the 16th letter in the alphabet.

$C = (16 + 13) \text{mod} 26 = 3$

So P is coded C.

L is the 12th letter in the alphabet:

$C = (12 + 13) \text{mod} 26 = 25$

L is coded Y(25th letter in the alphabet)

A is the 1st letter in the alphabet

$C = (1 + 13) \text{mod} 26 = 14$

A is coded N

N is the 14th letter in the alphabet

$C = (14 + 13) \text{mod} 26 = 1$

N is coded A

E is the 5th letter in the alphabet

$C = (5 + 13) \text{mod} 26 = 18$

E is coded R

So the correct answer is:

1. CYNARG

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