In base 5 the place values (from right to left) are the ones place, the 5's place and the 25's place. The highest digit you can write in any column is a 4.
333 would be (3 x 25) + (3 x 5) + (3 x 1) which is 93 in base 10.
30 would be (3x5) + (0 x 1) which is 15 in base 10.
The sum of 93 and 15 is 108 in base 10.
Now lets write that in base 5 - We can have 4 25's so there will be a 4 in the 25's column. Since 4 x 25 = 100 we still have to account for 8 to get to 108.
We can have 1 five in the 5's columns since 1 x 5 is 5. Now we have 3 left over which we can place in the one's column
Final answer 333₅ + 30₅ = 413₅
Answer:
b/(b+a)
Step-by-step explanation:
(1/a)-(1/b) :[ (b²-a²)/ab²]
first solve :
common denominator ab
(1/a)-(1/b) = (b-a)/ab
[b-a/ab] : [(b²-a²)/ab²]
when divide fraction ( division sign turn to (×) and flip the second fraction(reciprocal):
[b-a/ab] × [ab²/ (b²-a²)]
then simplify : ab²/ab = b
(b-a)×(b/b²-a²)
factorize : b²-a² = (b-a)(b+a)
(b-a)×(b/(b-a)(b+a)) simplify : (b-a)/b-a = 1
[(b-a)(b)]/[(b-a)(b+a)
b/b+a
Hello there!
Solve for z.
Explanation
↓↓↓↓↓↓↓↓↓↓↓
First you had to subtract by the numbers.
Then you add by 62 from both sides of the equation.
Simplify it should be the correct answer.
Answer⇒⇒⇒⇒z=121
Hope this helps!
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-Charlie
At the end of practice, Joseph will need to run another 1.75 miles or 1 3/4 miles.
To determine this we need to subtract the amounts he already has run during practice from the goal of 3 miles.
3 miles - 1/2 miles - 1/4 miles - 1/4 miles - 1/4 miles = 1.75 miles
