This is an easy half-life calculation because it involves an exact integer of half-lives. 1,104 days is precisely 8 half-lives. After each half-life, one half of the original remains.
So, after 8 half-lives you will have 1 / 2^8 of the original material left.
So we start with 30 grams and 1 / 2^8 =
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0.00390625</span></span></span>.
We are therefore left with (30 *
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0.00390625) or </span></span></span>
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0.1171875 grams of the original 30 grams of polonium.
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10.4 - 2 = 8.4
1/4(8.4) = 2.1........2 + 2.1 = 4.1 <==
First what you would have to do is distribute the reciprocal to the (d/3 + 2) and the d/3 is canceled out. You are left with h=6/d. When you put the h over 1 in a fraction, it stays the same. Like in trig, you switch the d and the h and you have d/1=6/h.
d=6/h
Answer:
10
Step-by-step explanation:
If 1 Gallon Cost 2.5$ and He Bought 4, Then Multiply 2.5 with 4 and we get the answer which is 10....
Answer:
10/1
Step-by-step explanation:
You do
6÷ 3/5
Flip the 3/5 then multiply
6 ° 5/3
Reduce the numbers with the greatest common factor 3
So 2•5
And that's 10