I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is
and the number of ways of drawing 3 aces and 2 2s is the same,
so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is
The total number of hands that can be drawn is
Then the probability of getting a full house is
First, you add 36 to both sides to get rid of -36. Then, the right side turns to 44 when add 8 and 36 together. Finally, your final answer is x<44
11.p=-8, 17-8=9
12.y=11, 3*11=33+16=46
13.t=4, 4*4=16-14=2
14.x=9, -9x 9*8=82-9=72-9=62
15.z=4, 12*4=48-18=30
16.g=0, 4*0=0, 7+0=7
17.x=4, 9*4=36-24=-3
18.q=3, 18*3=48+2=50
19.c=2, 3*2=6-4.5=4.1
20.y=4, 9+4=13+4.8=17.4
First off 3/9 and 6/9 are already common denominators. In some fractions you would need to find the least common denominator like in a problem like 1/2 + 4/5. Also 3/9 plus 6/9 results in 9/9 and 9/9 equals 1. Most fractions adding it subtracting results in a pan answer as a fraction but in this case it’s a whole number.
Answer:
8.898% will remain after 20000 years.
Step-by-step explanation:
First week need to know the half-life of carbon-14.
In this case it's 5,730 years.
There are calculators available online. (I'm too lazy to run through the equation.) 8.898% will remain after 20000 years.
