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3 years ago

Pls help I give brainliest to the best!!!!!!!!!!

Mathematics

2 answers:

Katarina [22]3 years ago

8 0

Answer:

${ {(m}^{6)} }^{3} \times {m}^{2} \div {m}^{ - 7}$

${m}^{6 \times 3} \times {m}^{2} \div {m}^{ - 7}$

${ m}^{18 + 2} \div {m}^{ - 7}$

${m}^{20 - ( - 7)}$

${m}^{20 + 7}$

${m}^{27}$

Neporo4naja [7]3 years ago

6 0

Answer:

−2m+3

Step-by-step explanation:

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Sandrena and her friends brought frozen yogurt for 55 cents per ounce.their total was $10.45.how many ounces did they buy?

lianna [129]

You would divide 10.45 by .55 and you would get 19 so 19 is your answer hope this helps

6 0

3 years ago

Find the value of x and the value of y for which (x,23) and (18,y) ate the points on the graph y=0.5x+15

shutvik [7]

Answer:

x=16; y=24

Step-by-step explanation:

for (x,23), 23=0.5x+15

x=16

for (18xy), y=0.5*18+15=24

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3 years ago

PLZ HELP ME WITH THIS WILL GIVE BRAINLIEST

frozen [14]

Answer:

Step-by-step explanation:

7 0

2 years ago

P=a+b+c solve for b<br> c=90x+35

Pavel [41]

Answer:

x=bc-35 over 90

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago