Answer:
The answer is the top right one since the total $96.35 is on the deposit side.
( i did this before and got it right btw)
Answer:
Step-by-step explanation:
Awnser is 29
It will be nice if you give me brainliest.Good luck!
circumference is C = πd, d = diameter.
we know the diameter is 60, so one time around the track is just C = π60 which if you plug that in your calculator, we get C ≈ 188.4955592153876.
The first thing we notice is that the function is reflected. So we can start by reflecting it with respect to the x-axis.
We do this by adding a negative sign in the function:
![\begin{gathered} f_0(x)=x^2 \\ f_1(x)=-f_0(x)=-x^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f_0%28x%29%3Dx%5E2%20%5C%5C%20f_1%28x%29%3D-f_0%28x%29%3D-x%5E2%20%5Cend%7Bgathered%7D)
Now, we have the function reflected, but in the wrong position. We can track its position by the vertex. It was originally at (0,0) and remains at (0,0) after the reflection.
But the final function have its vertex at (-5,0), so we have to translate the function 5 units to the left. we do this by adding 5 to the x in the function:
![f_2(x)=f_1(x+5)=-(x+5)^2](https://tex.z-dn.net/?f=f_2%28x%29%3Df_1%28x%2B5%29%3D-%28x%2B5%29%5E2)
Now, to check if there isn't any dilatation, we can check on other point in the graph to see if it checks out.
In the blue graph, we see the point (-3,-4), so let's input x = -3 and see if it checks out:
![f_2(-3)=-(-3+5)^2=-(2)^2=-4](https://tex.z-dn.net/?f=f_2%28-3%29%3D-%28-3%2B5%29%5E2%3D-%282%29%5E2%3D-4)
We got y = -4, so it checks out.
Thus, the answer is:
Point slope give a point on the line and the slope
it is best used when you are given a point on the line and the slope
or
it is also good when you knwo how to find the slope and you are given 2 points
I would go wiith first option that I said