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bagirrra123 [75]
3 years ago
12

A rock is thrown upward with a velocity of 14 meters per second from the top of a 20 meter high cliff, and it misses the cliff o

n the way back down. When will the rock be 12 meters from the water, below? Round your answer to two decimal places.
Mathematics
1 answer:
daser333 [38]3 years ago
3 0

Answer:

3.35 s after the rock is thrown, it will be 12 m above the water

Step-by-step explanation:

Hi there!

The height of the rock can be calculated using the following equation:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the rock at time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

Let´s place the origin of the frame of reference on the water so that y0 = 20 m.

Using the equation of height, we can obtain the time at which the rock is at a height of 12 m above the water:

y = y0 + v0 · t + 1/2 · g · t²

12 m = 20 m + 14 m/s · t + 1/2 · (-9.8 m/s²) · t²

subtract 12 to both sides of the equation:

0 = -12 + 20 m + 14 m/s · t - 4.9 m/s² · t²

0 = 8 m + 14 m/s · t - 4.9 m/s² · t²

Let´s solve the quadratic equation using the quadratic formula:

a = -4.9

b = 14

c = 8

t = [-b ± √(b² - 4ac)] / 2a

t = 3.35 s and t = -0.49 s

Since time can´t be negative, the rock will be 12 m above the water 3.35 s   after it is thrown.

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Answer:

The measure of ∠1 is 65°.

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The measure of ∠3 is 50°.

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Step-by-step explanation:

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We have an isosceles triangle which we can named it as ΔABC.

In which Length of AB is equal to length of BC.

And also m∠B is equal to m∠C.

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\angle 1+115\°=180\°\\\\\angle1=180\[tex]\therefore m\angle2=65\°-115\°=65\°[/tex]

Thus the measure of ∠1 is 65°.

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Since the given triangle is an isosceles triangle.

So, m\angle1=m\angle2

Thus the measure of ∠2 is 65°.

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Here ∠1, ∠2 and ∠3 are the three angles of the triangle.

So we use the angle sum property of triangle, which states that;

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\therefore \angle1+\angle2+\angle3=180\°

Now we put the values and get;

65\°+65\°+\angle3=180\°\\\\130\°+\angle3=180\°\\\\\angle3=180\°-130\°=50\°

Thus the measure of ∠3 is 50°.

For ∠4.

∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle2 +\angle 4 =180\°

Substituting the values of of angle 2 to find angle 4 we get;

65\°+ \angle 4 = 180\°\\\\ \angle 4 = 180\°-65\°\\\\\angle 4= 115\°

Thus the measure of ∠4 is 115°.

For ∠5.

∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle4 +\angle 5 =180\°

Substituting the values of of angle 4 to find angle 5 we get;

115\°+ \angle 5 = 180\°\\\\ \angle 5 = 180\°-115\°\\\\\angle 5= 65\°

Thus the measure of ∠5 is 65°.

Hence:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

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