Let r = usual driving rate
let t = usual driving time
We need to figure out t
The distance she covers in her usual time at her usual rate is r*t
The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)
Set this equal to each other and solve for t.
rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2
So her usual time is 2 hours. (There's probably a faster way to do this)
Step-by-step explanation:
105/30=3.5 hours for steven
105/15=7 hours for Kara.
they would be b at the same place in 7 hours when Kara catches up at 105km lol
1) The formula used for determining the confidence interval is
Sample mean +/- Critical value (or z-score corresponding to 90% confidence) * Standard
error of mean
8439 +/- 1.645 * 100/sqrt 25
8439 +/- 1.645 * 20
8439 +/- 32.9
2) The only difference in this case is finding the critical value i.e., z-score corresponding to 92% confidence which is 1.75 approximately
Then the confidence interval is
8439 +/- 1.75 * 100/sqrt 25
8439 +/- 1.75 * 20
8439 +/- 35
Lower limit is 8439 - 35 = 8404
The upper limit is 8439 + 35 = 8474
The compound inequality to show the possible length of the third side is; 25 ≤ x +9+12≤ 30 and it's solution is; 4 ≤ x ≤ 9.
<h3>What is the compound inequality to represent the situation?</h3>
The required compound inequality as described in the task content in terms of the sum of all three sides is;
25 ≤ x +9+12≤ 30
25 -9 -12 ≤ x; 4 ≤ x.
x +9+12≤ 30
x ≤ 30 -9 -12
x ≤ 9
The compound solution is therefore; 4 ≤ x ≤ 9.
Read more on compound inequality;
brainly.com/question/1485854
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Answer:
f(x) = 3x² - 14x - 5
Step-by-step explanation:
multiply the factors: (x + 1/3)(x - 5)
x² - 5x + 1/3x - 5/3
x² -14/3x - 5/3
multiply by 3 to eliminate fractions:
3x² - 14x - 5