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nirvana33 [79]
3 years ago
9

Evaluate the expression 5* – 31 for = 2. Help pls!

Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

the answer is 16

Step-by-step explanation:

5^2-3^2

25-9

16

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I have a question for you
egoroff_w [7]

Answer:

10 5/6

Step-by-step explanation:

First we have to make 2 1/6 into an improper fraction. This can be rewritten as 13/6. Now, we can multiply 13 by 5 and get 65/6. If we re-convert this into a mixed number, 6 goes into 65 10 times with a remainder of 5, so the final answer is 10 5/6.

4 0
3 years ago
Solve for pizza in the pie chart!
solniwko [45]

Answer:

24

Step-by-step explanation:

30% of the pie chart is pizza. 30% of 80 = 0.3 * 80 = 24

6 0
2 years ago
Read 2 more answers
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klasskru [66]

Answer:

slope is the rate at which a function progresses. y intercept a point that passes through they x axis when it is 0. ex) (0,9)

equation written as y=ax +b

b = y intercept

ax = slope

ax = y2-y1/x2-x1

take 2 random points

(0,3) (-2,0)

slope : 0-3/-2=0 = -3/-2 = 3/2

y intercept = 3 because x = 0 and y =3

<u>equation = y =3/2x + 3</u>

Step-by-step explanation:

3 0
3 years ago
Erik rides his motorbike 26 2/3 miles in 2/3 hour. What is Erik’s average speed in miles per hour?
frosja888 [35]

26 2/3 is equal to 80/3

80dividedby2/3 is

40/3

so its

13 1/3 miles per hour on average

6 0
2 years ago
Abby, Billy and Cathy fire one shot each at a target. The probability that Abby will hit the target is 1/5. The probability that
Tems11 [23]

Answer:

1.  0.0167

2. 0.2

3. 0.6

Step-by-step explanation:

Probabilities on Independent Events

If A and B are independent events (the occurrence of A doesn't affect the occurrence of B and vice-versa), then the probability that both events occur is

\displaystyle P(A\bigcap B)= \ P(A).P(B)

Being P(A) and P(B) the individual probability of each independent event

The probability that A does not occur is  

\displaystyle P(\bar{A})=1-P(A)

The probability that B does not occur is

\displaystyle P(\bar{B})=1-P(B)

The probability that C does not occur is

\displaystyle P(\bar{C})=1-P(C)

We have 3 independent events. We know that because they fire together, no mutual affectation can happen

.

The probability that Abby will hit the target is 1/5.  

\displaystyle P(A)=\frac{1}{5}

The probability that Billy will hit the target is 1/4.

\displaystyle P(B)=\frac{1}{4}

The probability that Cathy will hit the target is 1/3

\displaystyle P(C)=\frac{1}{3}

Part 1.

The probability that all three shots hit the target is

\displaystyle P(A\bigcap B\bigcap C)=\frac{1}{5}.\frac{1}{4}.\frac{1}{3}

\displaystyle P(A\bigcap B\bigcap C)=\frac{1}{60}

The probability that all three shots hit the target is

\displaystyle P= \frac{1}{60}=0.0167

Part 2.

The probability that only Cathy's shot hits the target is computed assuming Abby and Billy won't succeed

.

\displaystyle P(\bar{A}\bigcap \bar{B}\bigcap C)=P(\bar{A})\  P(\bar{B})\ P(C)=(1-\frac{1}{5})\ (1-\frac{1}{4})\ (\frac{1}{3})=\frac{4}{5}.\frac{3}{4}.\frac{1}{3}=\frac{1}{5}=0.2

3.

The probability that at least one shot hits the target is when one of them succeeds, two of them succed or all of them succeed

\displaystyle P(A\bigcap \bar{B}\bigcap \bar{C})+P(\bar{A}\bigcap {B}\bigcap \bar{C})+P(\bar{A}\bigcap\bar{B}\bigcap C)+P(A\bigcap B\bigcap \bar{C})+P(A\bigcap \bar{B}\bigcap C)+P(\bar{A}\bigcap B\bigcap C)+P(A\bigcap B\bigcap C)

But it's easier to find the negated probability of the above, i.e. we compute the probability that NO ONE hits the target and subtract it from 1

\displaystyle P=1-P(\bar{A}\bigcap \bar{B}\bigcap \bar{C})

P=1 -(1-\frac{1}{5})(1-\frac{1}{4})(1-\frac{1}{3})=1-\frac{4}{5}.\frac{3}{4}.\frac{2}{3}=1-\frac{2}{5}=\frac{3}{5}

P=0.6

6 0
3 years ago
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