-1/3(x - 15) = -4
step 1 : multiply both sides by -3, step 2 : add 15 to both sides
because when u multiply both sides by -3, this cancels out the -1/3 on the left side leaving u with : x - 15 = -4 * -3.....x - 15 = 12.....and then u would add 15 to both sides....giving u : x = 12 + 15.....x = 27
(4ab^2-5ba-2ba^2+a^2+4b^3+a^3)(2b+a)/ a-4b^2
The slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
<h3>How to find the slope of a line?</h3>
given that the equation is 5x - 3y = 2.
now write the equation in standard form y = mx + b
then -3y = 2 - 5x
y = -2/3 + 5x/3
y = 5/3x - 2/3
m 1*m 2 = - 1 is the formula for the slopes from a pair of perpendicular lines. where the slopes of the lines are m 1 and m 2.
Here m1 = 5/3 and m2 = -3/5.
Hence,the slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
Learn more about slope of the line from here:
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About 16 copies cost the same amounts
Answer:
C. c = -4
Step-by-step explanation:
you must get c by itself. you have to divide both sides by 10. this gets rid of the 10c and keeps both sides equal
-40/10 = c
c = -4
