Answer:
x<±1 and x< -3
Step-by-step explanation:
Given the inequality x^2-1/3x+9<0, we are to find the values of x that satisfies the inequality
x^2-1/3x+9<0
x^2-1/3x+9 (3x+9)²<0* (3x+9)²
(x^2-1)(3x+9) < 0
x²-1 < 0 and 3x + 9 <0
x²-1 < 0
x²<1
x<±√1
x<±1
Also 3x + 9 <0
3x < -9
x < -9/3
x < -3
Hence the required values of x are x<±1 and x< -3
Answer: 50
Step-by-step explanation: add DBC and ABD to get 50 ABC is 50
F(x) = rad(x)
g(x) = 3rad(x)
Substitute f(x) = rad(x) in g(x)
So g(x) = 3f(x)
So it's a vertical stretch.
The result of the given exponential expression is given as 1/8, 3^2, 1/5 and 5^-2
<h3>Properties of exponents</h3>
Some of the properties of exponents are expressed as shown below;
1) a^-n = 1/a^n
In order to answer the given questions, we will use the following properties above;
3^-4 = 1/3^4 where a is equivalent to 3 and n is equivalent to 4
Similarly;
1/2^3 = 2^-3 = 1/8
For the expression 1/3^-2
1/3^-2 = 1/(1/3^2)
1/3^-2 = 3^2
For the expression 5^-1
5^-1 = 1/5^1
5^-1 = 1/5
Also for 1/5^2
1/5^2 = 1/25 = 5^-2
Hence the result of the given exponential expression is given as 1/8, 3^2, 1/5 and 5^-2
Learn more on exponent here: brainly.com/question/11975096
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Answer:
The record is 593.
<u>To beat the record you need a greater number:</u>
<u>Options:</u>
- w ≥ 593 NO, it includes 593
- w > 593 YES
- w ≤ 593 NO, it includes 593 and smaller numbers
- 593 < w YES