The value of tan3x must be greater than the value of cos3x, because it is subtractable by a lesser value.
Answer: 4![\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%7D)
Step-by-step explanation:
You paid ..I’m broke so I can’t lol ..in my opinion it can be helpful sometimes because some of the questions don’t get answered or it’s someone just saying “I don’t know
An alternating series

converges if

is monotonic and

as

. Here

.
Let

. Then

, which is positive for all

, so

is monotonically increasing for

. This would mean

must be a monotonically decreasing sequence over the same interval, and so must

.
Because

is monotonically increasing, but will still always be positive, it follows that

as

.
So,

converges.
Answer:
The bounded area is 5 + 5/6 square units. (or 35/6 square units)
Step-by-step explanation:
Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)
Such that f(x) > g(x) in the given interval.
This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).
We want to find the area bounded by:
f(x) = y = x^2 + 1
g(x) = y = x
x = -1
x = 2
To find this area, we need to f(x) - g(x) between x = -1 and x = 2
This is:


We know that:



Then our integral is:

The right side is equal to:

The bounded area is 5 + 5/6 square units.