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r-ruslan [8.4K]
3 years ago
7

What is the LCD of 1/6 and 2/3

Mathematics
2 answers:
Illusion [34]3 years ago
8 0

Answer:

6

Step-by-step explanation:

We want to find the denominator that is common for both fractions

LCD means least common denominator of the smallest denominator that is common to both

6 and 3 , the smallest factor that is common to both is 6

nika2105 [10]3 years ago
5 0

Answer:

6

Step-by-step explanation:

  • What does LCD mean?

      LCD means Least Common Denominator

  • 1/6 and 2/3. You can easily see the least common denominator is 6 for 2/3 = 4/6 and 1/6 doesn't need to change.

Hope this helped!

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What is an equation of a parabola with a vertex at the origin and directrix x=4.75?
patriot [66]
An equation for the parabola would be y²=-19x.

Since we have x=4.75 for the directrix, this tells us that the parabola's axis of symmetry runs parallel to the x-axis.  This means we will use the standard form

(y-k)²=4p(x-h), where (h, k) is the vertex, (h+p, k) is the focus and x=h-p is the directrix.

Beginning with the directrix:

x=h-p=4.75
h-p=4.75

Since the vertex is at (0, 0), this means h=0 and k=0:

0-p=4.75
-p=4.75
p=-4.75

Substituting this into the standard form as well as our values for h and k we have:
(y-0)²=4(-4.75)(x-0)
y²=-19x
4 0
4 years ago
How many milliequivalents of sodium chloride are contained with 3 L of normal saline?
AVprozaik [17]

Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

3000ml*\frac{0.9g}{100ml}=27g=27000mg

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation (mEq=\frac{mg}{pE}) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

pE= \frac{23+35}{1}=\frac{58}{1} = 58

Finally we substitute in the mEq formula:

mEq=\frac{mg}{pE}=\frac{27000}{58}=466mEq

I hope you find this information useful! Good luck!

4 0
3 years ago
In this problem,y = 1/(x2 + c)is a one-parameter family of solutions of the first-order DEy' + 2xy2 = 0.Find a solution of the f
trasher [3.6K]

Differentiate the given solution:

y=\dfrac1{x^2+C}\implies y'=-\dfrac{2x}{(x^2+C)^2}

Substitute y and y' into the ODE:

-\dfrac{2x}{(x^2+C)^2}+2x\left(\dfrac1{x^2+C}\right)^2=0

and it's easy to see the left side indeed reduces to 0.

6 0
3 years ago
I don’t understand how to solve this problem??
Paraphin [41]
I think every angle below 90 degrees
7 0
3 years ago
Read 2 more answers
If a= -2, y = -3 and z = 4, find the values of the following algebraic expressions. -3az
kipiarov [429]

Answer:

24

Step-by-step explanation:

substitute the given values for a and z into the expression

- 3az

= - 3(- 2)(4) = 6 × 4 = 24

5 0
2 years ago
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