Answer:
-36x z^2 ( 10 y^2 z^2) ^ 1/3
Step-by-step explanation:
16. -9 ( 640 x^3 y^2 z^8) ^ 1/3
^1/3 is the cubed root
First I will separate
(ab)^y = a^y * b^y
-9 ( 640 ) ^ 1/3 x^3 ^ 1/3 y^2 ^ 1/3 z^8 ^ 1/3
Then we know a^b^c = a^(b*c)
-9 (64) ^ 1/3 (10)^ 1/3 x^(3 * 1/3) y^(2 *1/3) z^(8* 1/3)
Simplify
-9 (64) ^ 1/3 (10)^ 1/3 x^(1) y^(2 /3) z^(8/3)
-9* 4 (10)^ 1/3 x y^(2 /3) z^(8/3)
When the exponent is greater than 1, we can take out the whole number
z^ 8/3 = x^2 * x^2/3 for example
-9 *4 (10)^ 1/3 x y^(2 /3) z^2 z^(2/3)
Move everything to the left without fractional exponents
-36x z^2 ( 10 y^2 z^2) ^ 1/3
We have the next inequation
8-4x<56
-4x<56-8
-4x<48
-x<48/4
-x<12
x>-12
Solution: x>-12 or (-12,+∞)
Answer:
x={2,3}
Step-by-step explanation:
√5x-6=x
5x-6=x^2
x^2-5x+6=0
x^2-3x-2x+6=0
(x^2-3x)-(2x-6)=0
x(x-3)-2(x-3)=0
(x-2)*(x-3)=0
x-2=0
x=2
x-3=0
x=3
Answer:
the graph is 1/2, y intercept is -6, last one in -7
Step-by-step explanation:
Answer:
Five touchdowns were made in the game
Step-by-step explanation:
Here, we want to know the number of touchdowns made during the game.
We proceed as follows;
Let the number of touch downs be x
So the total points earned through touchdowns is 6 * x = 6x
The number of scores is 10 times
Let the number of extra kick be y which means that the number of conversions will be (y-1)
So the total number of score times will be ;
x + y + y-1 = 10
x + 2y = 11 •••••••••(i)
Now let’s work with points
Touch down points = 6 * x = 6x
Points from extra kick = 1 * y = y
Points from 2-point conversions = 2(y-1) = 2y - 2
So;
6x + y + 2y -2 = 37
6x + 3y = 37 + 2
6x + 3y = 39
divide through by 3
2x + y = 13 •••••••(ii)
So now solve simultaneously
From ii, y = 13 - 2x
Put this into i
x + 2(13-2x) = 11
x + 26 - 4x = 11
x -4x = 11-26
-3x = -15
x = -15/-3
x = 5
There are five touchdowns in the game