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Vinvika [58]
3 years ago
7

Five less than 6 times a number plus seven

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0
The Answer is: 6n-5+7
a_sh-v [17]3 years ago
4 0

Answer:

6n-5+7

6n+2 (simplified)

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What are the factors of 3x2 + 13x + 4?
padilas [110]
S<span>tep-1 : Multiply the coefficient of the first term by the constant </span><span> <span> 3</span> • 4 = 12</span> 

<span>Step-2 : Find two factors of </span> 12 <span> whose sum equals the coefficient of the middle term, which is  </span><span> 13 </span><span>.
</span><span><span>

-12   +   -1   =   -13</span><span>     
-6   +   -2   =   -8</span><span>     
-4   +   -3   =   -7</span><span>     
-3   +   -4   =   -7</span><span>     
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5 0
3 years ago
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Find the volume of the ellipsoid x^2+y^2+9z^2=64
yuradex [85]
Parameterize the ellipsoid using the augmented spherical coordinates:

\begin{cases}x=\frac18\rho\cos\theta\sin\varphi\\\\y=\frac18\rho\sin\theta\sin\varphi\\\\z=\frac38\rho\cos\varphi\end{cases}

Then the Jacobian for the change of coordinates is

\mathbf J=\dfrac{\partial(x,y,z)}{\partial(\rho,\theta,\varphi)}=\begin{bmatrix}\frac18\cos\theta\sin\varphi&-\frac18\rho\sin\theta\sin\varphi&\frac18\rho\cos\theta\cos\varphi\\\\\frac18\sin\theta\sin\varphi&\frac18\rho\cos\theta\sin\varphi&\frac18\rho\sin\theta\cos\varphi\\\frac38\cos\varphi&0&-\frac38\rho\sin\varphi\end{bmatrix}

which has determinant

\det\mathbf J=-\dfrac3{512}\rho^2\sin\varphi

Then the volume of the ellipsoid is given by

\displaystyle\iiint_E\mathrm dx\,\mathrm dy\,\mathrm dz=\iiint_E|\det\mathbf J|\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

where E denotes the spaced contained by the ellipsoid. In particular, we have the definite integral and volume

\displaystyle\frac3{512}\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=1}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\dfrac\pi{128}
4 0
3 years ago
How do I write 0.008 in word form? NEED HELP!!! ASAP...thanks! ​
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Point oh oh zero eight
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Answer:I don’t understand the question

Step-by-step explanation:

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200 grams of fertilizer are used for each tree in an orchard containing 1200 trees. at $2.75 per kilogram of fertilizer, how muc
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To determine the cost to fertilize the trees, you need to figure out how many kilograms of fertilizer are needed. With the information given, you can determine The number of grams needed to fertilize 1200 trees. To do this you would multiply 200 times 1200. This equals 240,000 grams. To convert this to kilograms, divide 240000g by 1000 g. Every group of 1000 g is 1 kg. The answer is 240 kilograms. Multiply 240 kg by the price of $2.75 per kilogram to get $660 as the cost.
4 0
3 years ago
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