How did Srinivasa ramanujan religion create a clash when he worked with G.H hardy
1 answer:
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Step-by-step explanation:
Answer:
He Melanie , use SOH CAH TOA to remember the trig functions
Step-by-step explanation:
for 14 they hyp = 22 and we know one angle of 45°, we also know that the triangle has a right angle or 90° and by inspection we can tell that the other angle is also going to be 45° so we know X and Y will be the same length, is why this is a good observation.
Use one of the trig functions with H in it b/c you know Hyp is 22, so,
SOH = Sin(Θ)= Opp / Hyp
Sin(45) = Opp / 22
Sin(45) * 22 = Opp
/ 2 * 22 = opp
11* = opp is the exact answer, if you would like some decimal places, it's 7.7781 units, both X and Y
for 15 we can use SOH again for the bigger triangle. we know the Hyp is 24 and the angle is 30°
Sin(30) = Opp / 24
Sin(30) *24 = Opp
12 = Opp ( Because I know Sin(30) = 1/2 )
Opp is the upright between the two triangles
Use CAH Cos(Θ) = Adj / Hyp
Cos(30) = Adj / 24
Cos(30) * 24 = Adj
/2 *24 =Adj
12 = Adj
Z = 12 or if you want some decimals 20.7846
Becasue the smaller triangle is also a 45° right triangle we know that the upright and side Y are the same lengths
then
Y = 12
You could use SOH or CAH to find the Hyp but, lets just resort to Pythagoras, and use his formula to find Hyp
Hyp =
Hyp =
hyp = 16.97
X = 16.97
:)
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What is the equation of the line parallel to y=-5x-9 and contains the point (-3, -3)?
First of all, parallel lines have the exact same slope.
So we know the slope of the line:- -5.
(enter -5, It's the number that belongs in the green box)
How about the y-intercept?
Well, since we're given the slope and a point that the line intersects, we can write the line's equation in point-slope form:-
y-y1=m(x-x1)
y-(-3)=-5(x-(-3)
y+3=-5(x+3)
y+3=-5x-15
y=-5x-18
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