All categories

3 years ago

4

Mathematics

2 answers:

tangare [24]3 years ago

7 0

Answer:

68 11/13

Step-by-step explanation:

So the question wants the problem 45+25-15÷13 to be solved. With this, use the order of PENDAS to solve the problem.

First, do -15 ÷ 13

This will get you -1 2/13

Next, add 45 and 25 together to get 70.

Lastly, do 70-1 2/13 to get 68 11/13.

faltersainse [42]3 years ago

5 0

Answer:

68 11/13

Step-by-step explanation:

You might be interested in

. A shipyard makes a container ship that can withstand the total amount of weight W, which is normally distributed with mean of

Debora [2.8K]

Answer:

the maximum number of containers that the ship can load is 170

Step-by-step explanation:

Given the data in the question;

W ~ N( 600, 60 )

S ~ N( 4n, 0.4√n )

p( W > S ) = 0.90

⇒ P( W - S > 0) = 0.9 ------ let this be equation 1

now, since W and S are independent

Mean( W - S ) = Mean( W ) - Mean( S 0 = 600 - 4n

and

SD( W - S ) = √( var(W) + var(S) ) = √( 60² + 0.4²n)

hence;

W - S ~ N( 600 - 4n, √( 60² + 0.4²n) )

now, from equation one, P( W - S > 0) = 0.9

$P( \frac{(W-S)-Mean(W-S)}{SD(W-S)} > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = 0.90$

$P( z > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = 0.90$

from z- table

$P( z > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = P( z >-1.282)$

$\frac{4n - 600}{\sqrt{60^2 + 0.4^2n} } = -1.282$ ------------------ let this be equation 2

now, we square both sides of equation 2

$\frac{(4n - 600)^2}{60^2 + 0.4^2n} } = (-1.282)^2$

$\frac{(4n - 600)(4n-600)}{3600 + 0.16n} } = 1.643524$

we cross multiply

16n² + 360000 - 4800n = 1.643524( 3600 + 0.16n )

16n² + 360000 - 4800n = 5916.6864 + 0.26296384n

16n² + 360000 - 5916.6864 - 4800n - 0.26296384n = 0

16n² + 354083.3136 - 4800.26296384n = 0

16n² - 4800.26296384n + 354083.3136 = 0

solving the quadratic equation, we know that;

x = -b±√( b² - 4ac ) / 2a

so we substitute

x = [-(-4800.26296384) ±√( (-4800.26296384)² - (4 × 16 × 354083.3136)] / [2×16]

x = [ 4800.26296384 ±√( 23042524.522 - 22661332.0704 ] / 32

x = [ 4800.26296384 ±√(381192.4516) ] / 32

x = [ 4800.26296384 ± 617.4078 ] / 32

Hence;

x = [ 4800.26296384 - 617.4078 ] / 32 or [ 4800.26296384 + 617.4078 ] / 32

x = 131 or 170

Therefore, the maximum number of containers that the ship can load is 170

5 0

3 years ago

Which of the following is a solution to this inequality? y greater than one half times x plus 2 (1, 4) (−1, 1) (2, 3) (0, 2)

Alecsey [184]

Answer:

(1, 4)

Step-by-step explanation:

Lets show first the inequality. Putting in numbers what greater than one half times x plus 2 means is:

y > (1/2)x + 2

The procedure is simple: take the points and replace them in the inequality to see which verifies.

(1, 4):

4 > (1/2)*1 + 2

4> 1/2+ 2

4 > 1/2 + 4/2

4> 5/2

8/2> 5/2 ---> I verifies!!!

(-1, 1)

1 > (1/2)(-1) + 2

1> -1/2 + 2

1 > -1/2 + 4/2

1 > 3/2 ---> Not verify!!

(2, 3):

2 > (1/2)*2 + 2

2 > 1 + 2

2 > 3 ---> Not verify!!!

(0, 2)

2 > (1/2)*0 + 2

2 > 2 ---> Not verify!!!

So, the only pair that verifies is (1, 4)

4 0

3 years ago

Read 2 more answers

Number 10 plz, i would appreciate it :)

Ket [755]

Answer:

s = 3

Step-by-step explanation:

Since the bigger triangle is isosceles, the two smaller triangles are equal to each other because line BD is an angle bisector of <B. We also know that since they are equal to each other, side AD and DC are congruent

knowing this, we can set the equation to 3s = s + 6

subtract s from both sides: 2s = 6

divide both sides by 2: s = 3

7 0

3 years ago

Suzy buys 2 shirts and 2 pairs of pants for 42 dollars at the store. Annette buys 3 shirts and 1 pair of pants for 37 dollars.

alexgriva [62]

Answer:

2s+2p = 42,

3s+p = 37,

2 shirts at 8 = 16,

2 pants at 13 = 26.

Hope this helps.

Step-by-step explanation:

7 0

4 years ago

Em uma enorme ampulheta, foram colocadas 40 kg de areia. Sabe-se que a areia escoa lenta e uniformemente à razão de 500g por dia

puteri [66]

Answer:

48 dias

Step-by-step explanation:

1000 gramas = 1 kg

A quantidade inicial de areia = 40kg

1 kg = 1000g

40kg = x

Multiplicação cruzada

1 kg × x = 40 kg × 1000g

x = 40 kg × 1000g / 1 kg.

x = 40,000 gramas

Somos informados de que 2/5 se esgotou.

Quantidade que foi drenada =

40,000 × 2/5

= 16,000 gramas foram drenados

Quantidade restante = 40,000 gramas - 16,000 gramas

= 24,000 gramas

A areia escoa a 500g por dia, portanto,

500g = 1 dia

24,000g = x

Multiplicação cruzada

500g × x = 24, 000 × 1

x = 24,000 g × 1 dia / 500

x = 48 dias

Restariam 48 dias para que a areia restante vazasse.

6 0

3 years ago