<span>7√7 - 2√28
2 sqrt(28) = 4 * sqrt(7)
7*sqrt(7) - 4*sqrt(7) =
3 * sqrt(7)
</span>
- Determine the surface area of the right square pyramid.
The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where
- b = base of the right square pyramid
- l = slant height of the right square pyramid.
In the given figure,
- base (b) = 4 ft.
- slant height (l) = 8 ft.
Now, let's substitute the values of b & l in the formula & solve it :-
So, the surface area of the right square pyramid is <u>8</u><u>0</u><u> </u><u>ft²</u><u>.</u>
Answer:
B
Step-by-step explanation:
There are 2 operations happening on the left side to x.
1. x is being multiplied by -4.
2. 2/5 is being added to -4x.
If you had a number for x, and you wanted to evaluate the left side, first, you would multiply the value of x by -4. Then you would add 2/5.
To solve an equation or an inequality, you do the opposite operation in the opposite order.
Since the second operation was add 2/5, to solve, you start by doing the opposite of the second operation. That means you subtract 2/5 from both sides.
Answer: B
Answer:
Step-by-step explanation:
list of these scientific notations
7.6 x 103
(Scientific Notation)
7.6 x 10^3
(use the caret symbol [^] to type or write)
7.60E+3
(Scientific E-notation)
7600
(Real Number)
I see 3 right triangles.
Right triangle: a² + b² = c²
a = long leg ; b = short leg ; c = hypotenuse
hypotenuse = EH
a = 6 - 3 = 3
b = 3 - 1 = 2
c² = 3² + 2²
c² = 9 + 4
c² = 11
c = √11
c = 3.32
hypotenuse = FG
a = 3 ; b = 1
c² = 3² + 1²
c² = 9 + 1
c² = 10
c = √10
c = 3.16
hypotenuse = EF
a = 3 ; b = 2
c² = 3² + 2²
c² = 9 + 4
c² = 11
c = √11
c = 3.32
perimeter = 3.32 + 3.16 + 3.32 + 2 = 11.8
