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Galina-37 [17]
3 years ago
7

Please help me with this ixl please

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

plot these points on the graph and connect them

Step-by-step explanation:

T(5,-10)

U(9,-10)

V(2,0)

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The company is going to choose three rows in each section to win the hats. There are
d1i1m1o1n [39]

answer is D i just took the test and i got it right

3 0
2 years ago
1Y, the number of accidents per year at a given intersection, is assumed to have a Poisson distribution. Over the past few years
miss Akunina [59]

Answer:

The probability that the intersection will come under the emergency program is 0.1587.

Step-by-step explanation:

Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.

Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.

For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.

Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).

W = \frac{X-\mu}{\sigma} = \frac{X-3}{1/2} = 2x-6

The values of \phi , the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program

P(X > 3.75) = P(2X-6 > 2*3.75-6) = P(W > 1) = 1-\phi(1) = 1-0.8413 \\= 0.1587

Download pdf
7 0
3 years ago
4.<br> Find the geometric mean of 4 and 12.<br><br><br> 24<br><br><br><br><br><br><br><br><br> 8
r-ruslan [8.4K]

The geometric mean of two numbers is the square root of their product.

sqrt{4 • 12}

sqrt{48}

sqrt{16} •sqrt{3}

4•sqrt{3}.

The geometric mean of 4 and 12 is

4•sqrt{3}.

5 0
3 years ago
True or false: Every kite is a rhombus, but not every rhombus is a kite.
horsena [70]

This is false. Kites can be shaped in many different ways so not all kites are rhombuses. Also, even the kites that look like rhombuses may not be rhombuses. Most kites have 2 pairs of sides with the same length. But, in order to be a rhombus all the sides have to be the same length but not all sides are the same length on a typical kite.

7 0
3 years ago
Two of them are drawn simultaneously from a deck of 48 cards.
Elina [12.6K]

The required probability is
a) both are cups is 0.05

b) At least one cup is 0.19

c) One is a cup and the other is a sword is   0.06

<h3 /><h3>What is probability?</h3>

Probability can be defined as the ratio of favorable outcomes to the total number of events.

a) for both are cups

P= 12*11/48*47
p = 0.05

b) for  At least one cup
p = 12*36/48*47
p = 0.19

c) for One is a cup and the other is a sword
p = 12*12/48*47
p = 0.06

Thus, the required probability is 0.05, 0.19, 0.06

Learn more about probability here:

brainly.com/question/14290572

<h3>#SPJ1</h3><h3 />

6 0
2 years ago
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