Wow i havent done this since 4th grade, it feels so weird doing it again :)
200,000+ 50,000+ 1,000 + 700 + 20 + 3
For t=0
<span>Allan borrows--------------------------- > 1870 dollars
for t=6 years
</span>F1 = P*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*6=6
we have
P1=1870
r=8%
m=1
t=6 years
F1 = 1870*(1 +(0.08/1))^6------------------ >2967.45 dollars
for t=2
Allan borrows--------------------------- > 1240 dollars
for t=6 years
F2 = P2*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*4=4
we have
P2=1240
r=8%
m=1
t=4 years------------> (6-2)=4 years
F2 = 1240*(1 +(0.08/1))^4------------------ >1687 dollars
F1+F2=2967.45+1687=4654.45 dollars
the answer is 4654.45 dollars
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
Answer: 6.35444444×10^13 gallons
Step-by-step explanation:
So a dishwasher uses 444 gallons of water per load.
That means it'll use 444*215215215 = 95555555460 gallons of water for 215215215 loads
Since washing dishes by hand takes 666 as much as water in comparison to using a dishwasher, we can do 95555555460x666 to find that you need 6.36399999×10^13 gallons of water to wash 215215215 loads.
The question asks for how much more water in gallons you can save, so do 6.36399999×10^13 - 95555555460 to get 6.35444444×10^13 gallons
