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Karo-lina-s [1.5K]
4 years ago
13

A student takes ten exams during a semester and receives the following grades: 90, 85, 97, 76, 89, 58, 82, 102, 70, and 67. Find

the five-number summary used in a boxplot. Which boxplot best represents the data?
Mathematics
2 answers:
den301095 [7]4 years ago
8 0
Formula: Minimum = first element of set First Quartile = (n+1)/4 Median = (n+1)/2 Third Quartile = 3(n+1)/4 Maximum = Last element of set. Solution:<span> The five number summary of ( 90, 85, 97, 76, 89, 58, 82, 102, 70, and 67) is, Minimum = 58 First Quartile = 70 Median: = 83.5 Third Quartile = 90 Maximum = 102</span>
MAXImum [283]4 years ago
8 0
Q1: 70
Median: 83.5
Q3: 90
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The diameter of a circle is 16 kilometers. Find the area of the circle.
Elden [556K]

The diameter of a circle is 16 kilometers. Then the area of the circle is 201.062 \mathrm{km}^{2}

<u>Solution:</u>

Given that , the diameter of a circle is 16 kilometers  

We have to find the area of the circle .

Radius is half of diameter.

\begin{array}{l}{\text { diameter }=2 \times \text { radius } \rightarrow \text { radius }=\frac{\text {diameter}}{2}} \\\\ {\rightarrow \text { radius }=\frac{16}{2} \rightarrow \text { radius }=8 \text { kilometers. }}\end{array}

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\begin{array}{l}{\text { area of a circle }=\pi \times r^2 \\ {\text { Area of a circle }=\pi \times 8^{2}=\pi \times 64=64 \times 3.14=201.062}\end{array}

Hence, the area of the circle is 201.062 km^2

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y=a(1+r)^w
y=75(1+.04)^w
y=75 (1.04)^w
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