Someone help please.

Mathematics

1 answer:

AnnyKZ [126]3 years ago

5 0

Answer:

Translation (the +5)

Dilation (the x 4)

Compression (the 3 to 1/3, and the x to 2-x)

Step-by-step explanation:

Brainliest, please!

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The ellipse with x-intercepts (2, 0) and (-2, 0); y-intercepts (0, 4) and (0, -4).

masya89 [10]

Answer:

$\dfrac{x^2}{4}+\dfrac{y^2}{16}=1$

Step-by-step explanation:

If the ellipse has its x-intercepts at points (2, 0) and (-2, 0) and y-intercepts at points (0, 4) and (0, -4), then its symmetric across the y-axis and across the x-axis.

Moreover,

$a=2\\ \\b=4$

The equation of such ellipse is

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1$

Hence, the equation of the ellipse is

$\dfrac{x^2}{2^2}+\dfrac{y^2}{4^2}=1\\ \\ \\\dfrac{x^2}{4}+\dfrac{y^2}{16}=1$

3 0

3 years ago

Solve for x: <br> 3x+2y=7

iVinArrow [24]

$3x+2y=7\ \ \ |subract\ 2y\ from\ both\ sides\\\\3x=7-2y\ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=\dfrac{7-2y}{3}}$

8 0

3 years ago

PLEASE HELPPP

Lelechka [254]

(x + a)/(ax) = b/x
a= 2
b = 5
(x + 2) /(2x) = 5/x
cross multiply
x * (x+2) = (2x)*5
x^2 + 2x = 10x
x^2 - 8x = 0
x ( x -8) = 0
We get two solutions
x = 0, 8
the solution 0 is extraneous
the solution 8 is valid.