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padilas [110]
3 years ago
6

What is the rate of 1090 miles on 15 gallons

Mathematics
1 answer:
Advocard [28]3 years ago
3 0
The rate is about 72 and 2/3 miles per gallon
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Would the answer be B or C? I know that their are 6 numbers but It confuses me because two of them are larger!
Travka [436]
Logical u would think it would be 1/6 but not all the pieces are equal so i would go with 1/8
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4 years ago
The data in the line plot show how many pages each student read last night. Which is the best measure of variability?
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3 years ago
What is the measure of angle G? Type only the number:
Alona [7]

Answer: 48

Step-by-step explanation:

total of all the degrees of the angles of the triangle is ALWAYS 180

let the measure of angle G be x

180 = 102+30+x

180 = 132+x

x = 48

5 0
3 years ago
While working at his neighborhood math tutoring center researching the comprehension level of the students Dion investigated tha
elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

While working at his neighborhood math tutoring center researching the comprehension level of the students Dion investigated that the distribution of the student test scores are normally distributed with a mean of 79.13 and a standard deviation of 6.34. What is the probability that the student scores less than 60.11

We solve using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

z = 60.11 - 79.13/6.34

6 0
3 years ago
10# A consumer advocacy group is doing a large study on car rental practices. Among other things, the consumer group would like
ella [17]

ANSWER:

104

STEP-BY-STEP EXPLANATION:

Given:

Standard deviation (σ) = 700

Confidence level = 95%

Mean error (Eμ) = 135

We have for a confidence level of 95%:

\begin{gathered} \alpha=100\%-95\%=5\%=0.05 \\  \\ \alpha\text{/2}=\frac{0.05}{2}=0.025 \\  \\ \text{ The corresponding Z value for \alpha/2 = 0.025 is as follows:} \\  \\ Z_{\alpha\text{/2}}=1.96 \end{gathered}

Now, we calculate the minimum value of the sample size as follows:

\begin{gathered} n=\left(\frac{Z_{\alpha\text{/2}}\cdot\sigma}{E}\right)^2 \\  \\ \text{ We replacing:} \\  \\ \:n=\left(\frac{1.96\cdot 700}{135}\right)^2 \\  \\ \:n=103.2858\cong104 \end{gathered}

The minimum sample size needed is 104

3 0
1 year ago
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