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slega [8]
2 years ago
15

Answer in Detail !!! ✨

Mathematics
1 answer:
Marrrta [24]2 years ago
3 0

Answer:

3300cm²

Step-by-step explanation:

30cm+30cm=60cm 60cm is the lengh of the whole joint structure.We will put it in the equation as "a".

heigh stays the same(10cm) because the pieces are not stacked one on top of the other.They are joined on their sides.We will put it as "c".

Widht also stays the same.its 15 cm and we will put it as letter "b".

So

a=60cm

b=15cm

c=10cm

We need to calculate the surface area of the entire joint structure.

1.First thing to do is to calculate the top part which is:

a*b=15*60=900cm²

2.The bootom side is the same 900cm².

3.The front side is:

a*c=60*10=600cm²

4.The back side is the same as front so it is 600cm².

5.The left side is:

c*b=10*15=150cm²

6.The right side is the same as the left and it is 150cm²

Now we just add it up.

S(surface)=900*2+600*2+150*2=3300cm²

If you want the whole exercise in one equation:

S=2*(a*b)+2*(a*c)+2*(b*c)

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And a wildlife preserve 46 ducks are captured tagged and then released. Later to her ducks are examined in four of the 200 ducks
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Answer:

2300

Step-by-step explanation:

We are given that

Out of 200 , four ducks are tagged.

We have to find the number of ducks in the preserve if 46 ducks are tagged.

Let x be the number of ducks in the preserve.

If number of tagged ducks increases then number of preserved ducks also increases.It is in direct proportion.

According to question

\frac{x}{46}=\frac{200}{4}

x=\frac{200\times 46}{4}

x=50\times 46

x=2300

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Serggg [28]
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Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

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2 years ago
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Answer:

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