It’s going to be -2 because the y intercept is when x=0.
The equation of the parabola in the vertex form is y = (x - 3
- 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier
In the above question, A parabolic equation is given as follows:
Y = x^2 - 6x + 4
The equation of the parabola in the vertex form is :
y = a (x - h
+ k
Where a is a multiplier in the equation and (h,k) are the coordinates of the vertex
So, in order to obtain this form, we will use the method of completing square :
Y = x^2 - 6x + 4
y =
- 6x + (9 -9) + 4
y = (x - 3
+ ( -9 + 4)
y = (x - 3
- 5
where, ( 3, -5) is the vertex of the parabola and 1 is the multiplier
Hence, The equation of the parabola in the vertex form is y = (x - 3
- 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier
To learn more about, parabola, here
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When adding fractions with even denominators, you will not get a whole number, there will be a 1/2. When adding fractions with odd denominators there will be a whole number.
Answer:
Segment BF = 16 is true.
Step-by-step explanation:
Since, DE is parallel to BC, so DE will divide AB and AC proportionally.
Hence,

⇒
{Since, given that AE = 12, EC = 18 and AD = 6}
⇒ BD = 9.
Again, since, EF is parallel to AB, so EF will divide BC and AC proportionally.
Hence, 
⇒
{Since, given that AE = 12, EC = 18 and FC= 24}
⇒ BF = 16.
Therefore, segment BF = 16 is true. (Answer)