1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svet_ta [14]
4 years ago
13

Plz help correct answer only!

Mathematics
1 answer:
Kitty [74]4 years ago
7 0

Answer:

A

Step-by-step explanation:

So the whole segment TV is made up of TU plus UV. In an equation:

TV=TU+UV

We already know that TV is 32 and UV is 20. Substitute:

32=TU+20

Subtract 20 from both sides:

TU=12

So, the length of TU is 12.

Our answer is A.

And we're done!

You might be interested in
Which theorem accurately completes Reason A?
klio [65]

hich theorem accurately completes Reason A

3 0
3 years ago
What is the vertex of the graph of y = 3x2 + 2x + 1?
Effectus [21]
We have that
y = 3x²<span>+ 2x + 1

step 1
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y -1= (3x²+ 2x)

step 2

Factor the leading coefficient

y -1= 3*(x²+ 2/3x)

step 3

Complete the square. Remember to balance the equation by adding the same constants to each side

y -1+(1/3)= 3*(x²+ (2/3)x+(4/36))

y-2/3=3*(x+2/6)²

the vertex is the point (-2/6, 2/3)------> (-0.33,0.67)

the answer is

(-0.33,0.67)

8 0
3 years ago
Read 2 more answers
Find the zero of each function and state the multiplicity of each zero. Please show all steps.
vodka [1.7K]

Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.


Step-by-step explanation:

1. y=(x+3)^3

y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3

Zero: x=-3 multiplicity 3.


2. y=(x-2)^2 (x-1)

y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.

Zeros: x=2 multiplicity 2; x=1 multiplicity 1


3. y=(2x+3)(x-1)^2

y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.

Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

4 0
3 years ago
The table shows the number of words a
garri49 [273]
B is correct

Total words =105+ 175+315= 595
Total minutes = 3+ 5 + 9 = 17
595/17= 35
If it is helpful t
5 0
3 years ago
What is 24% of 135??
KiRa [710]

Answer:

32.4

135 x 24% = 135 x 0.24 = 32.4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Other questions:
  • In your notebook, set up the following addition using a vertical format and find the sum of the given polynomials.
    14·2 answers
  • Please help me I been struggling with these two questions
    12·1 answer
  • The following table shows the number of hours some high school students in two towns spend riding the bus each week:
    13·1 answer
  • Statement and reasonings x+5=2x+5
    10·2 answers
  • Aiden wants to find the mass of a bowling ball. Which unit should he use?
    10·2 answers
  • Lanny’s credit card has an apr of 33%, calculated on the previous monthly balance. His credit card record for the last 7 months
    10·2 answers
  • HELP PLEASE ILL GIVE BRAINLIEST!!!!!!!!!
    13·2 answers
  • A patient is a member of a health plan that have a 20% discount from the provider and a 15% copay if the day's charges are to 10
    8·1 answer
  • I NEED HELP PLEASE I HAVE 10 MINS LEFT ON MY FINAL
    11·2 answers
  • A flower bed is in the shape of a rectangle. It measures7 yd long and 4 yd wide. Alonzo wants to use mulch tocover the flower be
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!