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Svet_ta [14]
3 years ago
13

Plz help correct answer only!

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

A

Step-by-step explanation:

So the whole segment TV is made up of TU plus UV. In an equation:

TV=TU+UV

We already know that TV is 32 and UV is 20. Substitute:

32=TU+20

Subtract 20 from both sides:

TU=12

So, the length of TU is 12.

Our answer is A.

And we're done!

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HELP PLS!!!!!!!!!!!!!!!!!!!
Rama09 [41]
Domain: {-5, 7}
Range: {-9, 4, 8}
6 0
3 years ago
You and your friend are selling tickets to a charity event. You sell 11 adult tickets and 8 student tickets for $158. Your frien
svetlana [45]
So what we have to do to solve this problem is to write down those values in 2 equations (one that represents what you sold and the other what your friend sold) compare them and find how much each ticket is worth.
First equation : 11x + 8y = 158
Where x = how much each adult ticket is
and y = how much each student ticket is

The second equation is : 5x + 17y = 152

Using the method of substitution , we can compare each equation side by side:
11x + 8y = 158
5x + 17y = 152
Now we need to set one of the variables of both equations so they are equal:
11(5)x + 8(5) = 158(5)
5(11)x + 17(11)x = 152(11)

55x + 40y = 790
55x + 187y = 1672

Then we subtract the second equation by the first one

55x-55x + 187y - 40y = 1672 - 790
147y = 882
y = 6
The we apply y to one of the equations to discover x :
11x + 8y = 158
11x + 8(6) = 158
11x + 48 = 158
11x = 110
x = 10

So the awnser is :
Each adult ticket (x) is $10
And each student ticket (y) is $8
I hope you understood my explanation,
7 0
3 years ago
Read 2 more answers
Identify an equation in slope-intercept form for the line parallel to y = -3x + 7
svet-max [94.6K]

Answer:

B

Step-by-step explanation:

B and D are the only ones with the same slope (-3x) which is required for the line to be parallel.

and if you graph it out, you will find that B is the correct answer because it passes through (2,-4).

5 0
3 years ago
Express p in terms of q if
Irina-Kira [14]

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

8 0
3 years ago
Company A charges $50 rental fee and $20 per hour.Then Company B charges $35 rental fee and $25 per hour.At which hour do both c
KengaRu [80]
For company a it would be at the 8th hour and they would be 210 and for company b it would be at the 7th hour
3 0
3 years ago
Read 2 more answers
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