Answer:
 External respiration: CO2 diffuses into the blood
Explanation:
External respiration is also called the pulmonary gas exchange. It refers to the diffusion of O2 from the air in the alveoli of the lungs to blood in pulmonary capillaries and diffusion of CO2 in the opposite direction from the capillary blood into the alveolar air. External respiration in the lungs is responsible for oxygenation of deoxygenated blood coming from the right side of the heart. The oxygenated blood is then returned to the left side of the heart.  
 
        
             
        
        
        
<span>the glucose-sodium cotransporter in animals, Na+ moves back into the cell down its electrochemical gradient, providing the energy for glucose to move into the cell against its concentration gradient.  
</span>It makes sense css <span> glucose is cotransported with Na+ ions</span>
<span>In cotransport, the energy required to move one solute against its concentration or electrochemical gradient is provided by an ion moving into the cell down its electrochemical gradient. </span>
        
             
        
        
        
Answer:
In the covalent bond between oxygen and hydrogen, the oxygen atom attracts electrons a bit more strongly than the hydrogen atoms. The unequal sharing of electrons gives the water molecule a slight negative charge near its oxygen atom and a slight positive charge near its hydrogen atoms.
Hope it helps!
 
        
                    
             
        
        
        
Answer:
linkage with approximately 33 map units between the two gene loci
Explanation:
If two genes are not linked, number of recombinants and parental offspring will be equal. Here it is clearly visible that recombinants are less than parental offspring hence the genes are linked. Given, the offspring are in following numbers:
AaBb = 106 = Parental
aabb = 94 = Parental
Aabb = 48 = Recombinant
aaBb = 52 = Recombinant
Recombination frequency = (Number of recombinants/ Total progeny) * 100 = (100/300) * 100 = 33.33 %
1% recombination frequency= 1 map unit of distance between the two gene loci. So here the distance between the two gene loci is approximately 33 map units.
Hence, these results are consistent with linkage with approximately 33 map units between the two gene loci