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Vlad1618 [11]
2 years ago
6

Exchange of gases in plants occur through:

Biology
1 answer:
yuradex [85]2 years ago
4 0

Answer:

(A): through the stomata

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The most appropriate microscope for visualizing a living bacterial cell that is non-pigmented and unstained is:
sammy [17]
The electron microscope
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3 years ago
Which of the following processes is NOT properly matched with its description?
Viefleur [7K]

Answer:

External respiration: CO2 diffuses into the blood

Explanation:

External respiration is also called the pulmonary gas exchange. It refers to the diffusion of O2 from the air in the alveoli of the lungs to blood in pulmonary capillaries and diffusion of CO2 in the opposite direction from the capillary blood into the alveolar air. External respiration in the lungs is responsible for oxygenation of deoxygenated blood coming from the right side of the heart. The oxygenated blood is then returned to the left side of the heart.  

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Part A - The glucose-sodium cotransporter
Ulleksa [173]
<span>the glucose-sodium cotransporter in animals, Na+ moves back into the cell down its electrochemical gradient, providing the energy for glucose to move into the cell against its concentration gradient.  
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5 0
3 years ago
Why does the oxygen atom in a water molicule have a negative charge
scZoUnD [109]

Answer:

In the covalent bond between oxygen and hydrogen, the oxygen atom attracts electrons a bit more strongly than the hydrogen atoms. The unequal sharing of electrons gives the water molecule a slight negative charge near its oxygen atom and a slight positive charge near its hydrogen atoms.

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3 0
2 years ago
Read 2 more answers
Assume that a cross is made between AaBb and aabb plants and that the offspring occur in the following numbers: 106 AaBb, 48 Aab
Elenna [48]

Answer:

linkage with approximately 33 map units between the two gene loci

Explanation:

If two genes are not linked, number of recombinants and parental offspring will be equal. Here it is clearly visible that recombinants are less than parental offspring hence the genes are linked. Given, the offspring are in following numbers:

AaBb = 106 = Parental

aabb = 94 = Parental

Aabb = 48 = Recombinant

aaBb = 52 = Recombinant

Recombination frequency = (Number of recombinants/ Total progeny) * 100 = (100/300) * 100 = 33.33 %

1% recombination frequency= 1 map unit of distance between the two gene loci. So here the distance between the two gene loci is approximately 33 map units.

Hence, these results are consistent with linkage with approximately 33 map units between the two gene loci

3 0
3 years ago
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