Answer:
-xz - 2x²- 2yz
Step-by-step explanation:
Multiply out (x-2y)z-2x(x+z)
(x - 2y)z - 2x( x + z)
Rearrange
z(x - 2y) - 2x(x + z)
Open bracket by multiplying by letters outside bracket
xz - 2yz - 2x² - 2xz
Collect like terms
xz -2xz - 2x² - 2yz
-xz - 2x² - 2yz
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Let's solve your equation step-by-step.
2.5(6x−4)=10+4(1.5+0.5x)
Step 1: Simplify both sides of the equation.
2.5(6x−4)=10+4(1.5+0.5x)
(2.5)(6x)+(2.5)(−4)=10+(4)(1.5)+(4)(0.5x)(Distribute)
15x+−10=10+6+2x
15x−10=(2x)+(10+6)(Combine Like Terms)
15x−10=2x+16
15x−10=2x+16
Step 2: Subtract 2x from both sides.
15x−10−2x=2x+16−2x
13x−10=16
Step 3: Add 10 to both sides.
13x−10+10=16+10
13x=26
Step 4: Divide both sides by 13.
13x
13
=
26
13
x=2
Answer:
x=2
Answer:
C. 1
Step-by-step explanation:
Multiply every answer until you get an answer more than 6, and in this case it was C
Answer:
Step-by-step explanation:
Divide both sides by 
:
Simplify:
Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
