Solve for x. A. 37 B. 27 C. 30 D. 31
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If we plot that point we find ourselves in QIV. The distance along the x axis is 4, and the distance down from that point is -3. If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle. We need its measure. Using Pythagorean's theorem, 
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. We see that c = 5. We need now to find the secant of that right triangle. Secant if the co-identity of cosine which is side adjacent over hypotenuse. That means that secant is the hypotenuse over the side adjacent. So our secant theta = 5/4