All categories

2 years ago

Okay this app getting addicting

Mathematics

2 answers:

kompoz [17]2 years ago

8 0

FAXT

like i started today but i can't stoppppp

o-na [289]2 years ago

6 0

Bruh frrrrr I need to stop spending all my time on here

You might be interested in

Use the divisibility rules to determine which of the following numbers 504 is divisible by.

Reika [66]

Answer:

504 is divisible by 2, 3, and 7. It is not divisble by 5 or 11

Step-by-step explanation:

C'mon. Use a calcultor.

3 0

3 years ago

Help me please I don’t know what to do someone help meeee

Hunter-Best [27]

Answer:

brainliest plz

Step-by-step explanation:

5 0

3 years ago

267.26 rounded to the nearest tenth

Lady_Fox [76]

267.3
1 2 3 4 STAYS THE SAME
5 6 7 8 9 ROUNDS UP

6 0

3 years ago

Alice plants carrots in a rectangular garden bed. The garden bed has a width of 1.5 meters

mojhsa [17]

Answer:

1. L= A/W

2. 4m

Step-by-step explanation:

We can define this problem as a word problem relating to mensuration of flat shapes, a

rectangle

1. Let the length be L and the width be W

Given

Area A= 6m²

W= 1.5m

We know that the area of a rectangular shape is

Area = L x W

The expression for the length is

L= A/W

2. The solution for the length is

6=1.5L

L= 6/1.5= 4m

8 0

3 years ago

Read 2 more answers

Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers

Mars2501 [29]

Answer:

a) Let $\frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}$ .

Observe that

$\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.$

Observe that

$\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.$

Observe that

$\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.$

Observe that

$\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}$

3 0

3 years ago