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swat32
3 years ago
6

A 16-ft steel beam is to be cut into two pieces so

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

8.5 feet and 7.5 feet.

Step-by-step explanation:

Hope this helps :)

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10. Which of the following sets is written in order from least to greatest?
Vika [28.1K]

Answer:

B

Step-by-step explanation:

The answer is B because if you convert 1/4 into a decimal you get 0.25, and that is less than 0.5 and 0.75. I hope this helps!

5 0
3 years ago
Find the area of the following rectangle (the figure is not drawn to scale)
Sophie [7]

Answer:

<h2>204 units²</h2>

Step-by-step explanation:

It's a rectangle. Therefore the opposite sides are congruent.

We have the equation:

2x + 4 = 12              <em>subtract 4 from both sides</em>

2x = 8       <em>divide both sides by 2</em>

x = 4

Put the value of x to the expression 4x + 1:

4(4) + 1 = 16 + 1 = 17

Therefore we have the rectangle with dimesions 17 × 12.

The area of the rectangle:

A = (17)(12) = 204

8 0
4 years ago
Mary has 2 1/3 yards of fabric.<br><br><br><br> She wants to cut the fabric into 1/6 yard strips.
ss7ja [257]

Answer:

so what should we do it is incomplete answer

Step-by-step explanation:

42

7 0
3 years ago
Read 2 more answers
Please help! 10 points and brainlyist!!
yarga [219]

Answer:

1.80 in^3

1.0 fluid ounces^3

Step-by-step explanation:

volume of a cone = 1/3 πr²h

π = 3.14

r = 2.2 / 2 = 1.1

h = the value of h can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

1.8² = 1.1² + b²

3.24 = 1.21 + b²

3.24 - 1.21 = b²

2.03

b = √2.03 = 1.42

Volume = 1/3 x 3.14 x 1.21 x 1.42 = 1.80 in^3

1.80 x 0.554 = 1.0 fluid ounces^3

5 0
3 years ago
Need help with all parts please show you work for each part
bezimeni [28]
Vinegar is the x or horizontal oil is the y or vertical
\frac{3}{2}  =  \frac{y}{x}  \\ 3x = 2y \\ y =  \frac{3}{2} x
the point represent the amount of vinegar and oil so for 1 tbsp vinegar you need 1.5tbsp oil
4 0
3 years ago
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