first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.
let's notice the vertex, or U-turn, is at (-2, 2)
Select the function that matches the graph. y = 3x y = 3x2 + 1 y = 3x - 1 y = 3x + 1
2 answers:
Answer:
The graph is missing, but we can draw and describe each option.
<h3>Choice 1</h3>This is a linear function which passes throuhg the origin of the coordinate system because it doesn't have the constant which is the y-intercept of the line.
The first image attached shows this function.
<h3>Choice 2</h3>This is a quadratic function. Its graph belongs to a parabola, all quadratic functions are represented by a parabola. In this case, the parabola has a vertex at (0,1). The second image attached shows this function.
<h3>Choice 3</h3>This is also a linear function, which is parallel to the first function, because they have the same slope of 3. But this one has y-intercept at (0,-1). The third image attached shows this function.
<h3>Choice 4</h3>This is also a linear function parallel to function 1 and function 3. The fourth image attached shows its graph. In this case, the line has y-intercept at (0,1).
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