Answer:
Step-by-step explanation:
x²+10x+21=0
x²+10x+(10/2)²-(10/2)²+21=0
x²+10x+25-25+21=0
(x+5)²-4=0
(x+5)²=4
(x+y)²=(x+y)(x+y)=x(x+y)+y(x+y)=x²+xy+xy+y²=x²+2xy+y²
(x+y)²=x²+2xy+y²
coefficient of x=2y
y²=[(coefficient of x)/2]²=(2y/2)²=y²
-8-5b+7+5b
add +5b to -5b to get 0.
-8+7 = -1
Answer is -1.
The vertex form of the equation is:
y = a ( x - h )² + k
- 81 = a ( 0 - 6 )² + 27
- 81 = 36 a + 27
- 108 = 36 a
a = - 108 : 36
a = - 3
y = - 3 ( x - 6 )² + 27
y = - 3 ( x² - 12 x + 36 ) + 27
y = - 3 x² + 36 x - 108 + 27
y = - 3 x² + 36 x - 81
y = - 3 ( x² - 12 x + 27 )
x² - 12 x + 27 = 0
x² - 9 x - 3 x + 27 = 0
x ( x - 9 ) - 3 ( x - 9 ) = 0
( x - 9 ) ( x - 3 ) = 0
x 1 = 3, x 2 = 9
Answer:
The x-intercepts are ( 3, 0 ) and ( 9, 0 ).
The entire shipment contains 9 2/7 tons of sugar
Step-by-step explanation:
- Step 1: Find the total amount of sugar in the entire shipment.
Number of containers in the shipment = 4 1/3 = 13/3
Number of tons of sugar = 2 1/7 = 15/7
⇒ Total amount of sugar = 13/3 × 15/7 = 65/7 = 9 2/7 tons
