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nikklg [1K]
2 years ago
15

Please help!!

Mathematics
1 answer:
solniwko [45]2 years ago
3 0

Answer:

C

Step-by-step explanation:

A line parallel to a side of the triangle and it intersects the other two sides, then it divides those sides proportionally, that is

\frac{a}{b} = \frac{d}{c} → C

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Zachary is making dumplings. If he uses cup of dough for each dumpling, how
LekaFEV [45]

Answer:

11 cups of dough

Step-by-step explanation:

1 cup x 11 dumplings = 11 cups of dough needed

6 0
3 years ago
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Claire is on a business trip. She’ll be traveling from Liverpool, England, to Melbourne, Australia. The latitude value of Liverp
Alekssandra [29.7K]

Answer:

The change in latitude, Δφ, from Liverpool to Melbourne is 91.22° south

The change in longitude, Δλ, from Liverpool to Melbourne is 147.95° East

Step-by-step explanation:

The parameters given are;

The latitude of Liverpool is 53.41°

The longitude of Liverpool is -2.99°

The latitude of Melbourne is -37.81°

The longitude of Melbourne is 144.96°

The change in latitude from Liverpool to Melbourne = Δφ

Δφ = 53.41° - (-37.81°) = 53.41° + 37.81° = 91.22°

The change in latitude, Δφ, from Liverpool to Melbourne = 91.22° south

The change in longitude from Liverpool to Melbourne = Δλ

Δλ = -2.99° - 144.96°  = -147.95°

Therefore the change in longitude from Liverpool to Melbourne = 147.95° East.

6 0
3 years ago
Read 2 more answers
Which statements are true about the interquartile range? Select all that apply. Subtract the lowest and highest values to find t
katen-ka-za [31]

Answer:

The correct options are:

Interquartile ranges are not significantly impacted by outliers.

Lower and upper quartiles are needed to find the interquartile range.

The data values should be listed in order before trying to find the interquartile range.


The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range.

The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

6 0
3 years ago
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8/3 write as a mixed fraction
Helen [10]
8/3 as a mixed fraction is 2_2/3
3 0
2 years ago
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Abby's cat weighs 18 pounds. Her dog weighs 2 pounds more than half her cat's weight.write and evaluate an expression to show ho
Vaselesa [24]

Answer:

11 pounds

Step-by-step explanation:

Just divide the cats weight by 2 and then add 2

(18)/2 + 2

7 0
2 years ago
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