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3 years ago

The point (-3,-1) is the midpoint of (x,y) and (5,4). Find the point (x,y).

Mathematics

1 answer:

nirvana33 [79]3 years ago

4 0

Answer:

(-11, -6)

Step-by-step explanation:

Find the distance between the midpoint, (-3, -1) and (5, 4). This can be calculated by finding the difference between the x coordinates and y coordinates.

-3 - 5 = -8 (distance between x coordinates)

-1 - 4 = -5 (distance between y coordinates)

Find the point (x, y) by subtracting 8 from the midpoint's x value, and then subtracting 5 from the midpoint's y value.

-3 - 8 = -11

-1 - 5 = -6

So, the point (x, y) is (-11, -6)

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What are the steps for drawing the midsegment of any triangle on a coordinate plane

marin [14]

This construction uses Constructing the Perpendicular Bisector of a Line Segment to find the midpoints of the sides.

To construct a midsegment, find the midpoint of two sides. This can be done by drawing a perpendicular bisector on one side of the triangle.

I hope my answer has come to your help. God bless and have a nice day ahead!

3 0

3 years ago

If sin θ=4/5 and 90°<θ<180°, what is cos θ?

34kurt

Answer:

Cos ∅ = 3/5

BUT COSINE IS NEGATIVE IN THE SECOND QUADRANT.

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3 years ago

2 tan 30° II 1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

A triangle has one angle that measures 40 and another that measures 38. What is the measure of the triangles third angle

mr_godi [17]

Answer:

102°

Step-by-step explanation:

that's the answer because 40+ 38 = 78. then 180- 78 = 102. Remember that in tringles, all three angles should add up to 180°

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3 years ago

The wingspan of different species of birds is as follows:

grigory [225]

A. albatross - blue jay = 3 1/2 - 39/100
================== (3*2)+1/2 - 39/100
================== 7/2 - 39/100
================== 311/100
================== 3.11

b. Golden eagle - seagull = 2 1/4 - 11/5
======================= (2*4)+1/4 - 11/5
======================= 9/4 - 11/5
======================= 1/20
======================= 0.05

3 0

3 years ago