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katrin2010 [14]
3 years ago
10

PLEASE HELP! WILL GIVE BRAINLIEST ANSWER!

Mathematics
2 answers:
zvonat [6]3 years ago
6 0
They will have the same coordinate,so we can just find out x and y

3x-y=9(1)
y=-2x+11(2)
Put (2) into(1)
3x-(-2x+11)=9
3x+2x-11=9
5x=20
x=4
Put x=4 into (1)
3(4)-y=9
12-y=9
y=3
Answer is A
Drupady [299]3 years ago
4 0
(-4, 3) I think, not sure. But I hoped this helped.
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The answer is 14

Step-by-step explanation:

t - 7 ; t = 20

20 - 7 = 14

Thus, The answer is 14

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What is the slope of the line
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Answer:

The slope is 7/7 or 1.

Step-by-step explanation:

Find any two points on the line. I chose (0,7) and (-7,0).

Put rise over run.

7-0

———

0 – -7

this would equal 7/7 which simplifies to 1.

Hope this helped!

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The sum of the roots of the quadratic 5x^2 - 6x + 1 = 0 is
MatroZZZ [7]

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3 years ago
What is the slope of the line for BOTH graphs? Are the slopes the same or different?
Y_Kistochka [10]

Answer:

both are -10

Step-by-step explanation:

#1

x1 y1  x2 y2

1.5 180  6 135

(Y2-Y1) (135)-(180)=   -45  ΔY -45

(X2-X1) (6)-(1.5)=    4.5  ΔX 4.5

slope= -10          

B= 195          

Y =-10X +195

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~    

#2

x1 y1  x2 y2

1 175  8 105

   

(Y2-Y1) (105)-(175)=   -70  ΔY -70

(X2-X1) (8)-(1)=    7  ΔX 7

slope= -10          

B= 185          

Y =-10X +185    

7 0
3 years ago
Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t
baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of calculators coming out of the production lines have a defect.

This means that p = 0.05

Fifty calculators are randomly selected from the production line and tested for defects.

This means that n = 50

What is the probability that exactly 2 calculators are defective?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{50,2}.(0.05)^{2}.(0.95)^{48} = 0.2611

0.2611 = 26.11% probability that exactly 2 calculators are defective.

3 0
3 years ago
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