3 years ago

Can anyone help please?

Mathematics

1 answer:

Lina20 [59]3 years ago

8 0

Ok ok im gonna with C but if it’s wrong i am sooo sorry

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-6h plus 4 - 3plus h equals 11

olga55 [171]

$- 6h + 4 - 3 + h = 11$
So we start by combining like terms;
$- 6h + h = - 5h$
$4 - 3 = 1$
Now we have;
$- 5h + 1 = 11$
We then subtract 1 from both sides;
$- 5h + 1 = 11$
$- 5h = 10$
Then we divide both sides by 5;
$- 5h = 10$
$- 5h \div - 5h = h$
$10 \div - 5h = - 2$
Leaving the final answer to be h = -2

5 0

3 years ago

(2a+b)^2÷(3b-1) when a= -2 and b=5

WINSTONCH [101]

Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)

3×5 = 15:
(5 - 2×2)^2/(15 - 1)

| 1 | 5
- | | 1
| 1 | 4:
(5 - 2×2)^2/14

2 (-2) = -4:
(-4 + 5)^2/14

5 - 4 = 1:
1^2/14

1^2 = 1:

Answer: 1/14

6 0

3 years ago

In his boat, Sheldon can travel 45 mi downstream in the same time that it takes to travel 9 mi upstream. If the rate of the curr

Nataliya [291]

Answer:

9 mph

Step-by-step explanation:

-let x be the speed of current and t be time. The speed equation for both directions can then be represented as:

$Speed=\frac{Distance}{Time}\\\\\#Upstream\\(u-6)t=9\\\\\#Donwstream\\\\(u+6)t=45$