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4 years ago

10

The coordinates below represent two linear equations. How many solutions does this system of equations have? Line 1 x y –1 6 0 4

Line 2 x y 0 7 1 5 A. 0 B. exactly 1 C. exactly 2 D. infinitely many

1 answer:

iren2701 [21]4 years ago

8 0

I think you need to retype this one. The formatting makes this question difficult to understand.

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Please help due tomorrow for Questions C. (A),(B)

8090 [49]

A.
Selena makes 0.05 posters per minute
Jason makes 0.2 posters per minute
Kai makes 0.2 posters per minute
Enrique makes 0.1 posters per minute
Andre makes 0.5 posters per minute

B.
Selena makes the least posters per minute
Andre makes the most posters per minute

C.
If Selena made 80 posters in 8 minutes, she would be making 10 posters per minute.
Selena now makes the most posters and Enrique makes the least.

Hope this helps!! :)

8 0

4 years ago

A survey reports that the probability a person has blue eyes is 0.10. Assume that 4 people are randomly selected at Miramar Coll

marissa [1.9K]

Answer:

0.344 = 34.4% probability that at least 1 of them have blue eyes.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have blue eyes, or they have not. The probability of a person having blue eyes is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A survey reports that the probability a person has blue eyes is 0.10.

This means that $p = 0.1$

4 people are randomly selected at Miramar College

This means that $n = 4$

Find the probability that at least 1 of them have blue eyes.

Either none of them have blue eyes, or at least one do. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.656$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.656 = 0.344$

0.344 = 34.4% probability that at least 1 of them have blue eyes.

4 0

3 years ago

If f(x)=2^x-1 and g(x)= x^2-1, determine the value of (f o g)(3)

zimovet [89]

Answer: 4

Step-by-step explanation:

( f o g ) (3) means f(g(3)) so...

First: plug 3 into g(x) = x^ (2-1)

3^ (2-1) is 3^1 = 3

Next: plug 3 into f(x)= 2^(x-1)

2^(3-1) is 2^(2) > 2×2 = 4

3 0

3 years ago

2x + 8y=5 solve for x

lora16 [44]

Answer:

$x=\frac{5-8y}{2}$

Step-by-step explanation:

1 Equation is given, so solving for "x" would mean an expression for "x", where

x = SOMETHING

First, we need to isolate x, so we need to take "8y" to the other side, we have:

$2x+8y=5\\2x=5-8y$

Now, since we don't have "x" isolated yet, we need to take out the 2, so we will divide both sides by 2 to get x isolated. Shown below:

$2x=5-8y\\x=\frac{5-8y}{2}$

So, x has this expression $x=\frac{5-8y}{2}$

8 0

3 years ago

50 POINTS! Could someone answer these three questions? <br><br> I’ll mark Brainliest

san4es73 [151]

Answer:

56

Step-by-step explanation:

7 0

3 years ago