The <em>correct answers</em> are:
5x²+70x+245 ≥ 1050; and
Yes.
Explanation:
Let x be the width of the tablet. Since the width of the TV is 7 inches more than the tablet, the width of the TV would be x+7.
The length of the TV is 5 times the width; this makes the length 5(x+7) = 5x+35.
The area of the TV would be given by
(x+7)(5x+35).
Since Andrew wants the area to be at least 1050, we set the expression greater than or equal to 1050:
(x+7)(5x+35) ≥ 1050
Multiplying this, we have:
x*5x+x*35+7*5x+7*35 ≥ 1050
5x²+35x+35x+245 ≥ 1050
Combining like terms,
5x²+70x+245 ≥ 1050
To see if 8 is a reasonable width for the tablet, we substitute 8 for x:
5(8²)+70(8)+245 ≥ 1050
5(64)+560+245 ≥ 1050
320+560+245 ≥ 1050
1125 ≥ 1050
Since this inequality is true, 8 is a reasonable width.
Let the number of packages of hot dogs be D, and the number of packages of hamburgers be H. We can set up the equations:
1.60D + 5H = 23
D + H = 8 ---> which we can subtract D on both sides and get: H = 8 - D
1.6D + 40 - 5D = 23, -3.4D = -17, D = 5. The number of packages of hot dogs we buy are 5.
Now, we plug that into D + H = 8, and get 5 + H = 8. Subtracting by 5 on both sides of the equation, we get H = 3. So the number of packages of hamburgers we buy are 3.
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Hope this helps!
Answer:
Neither
Step-by-step explanation:
To verify, we substitute the values in the equations:

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.
70-q-q-2q= 80
combine like terms first
so you get 70-4q= 80
subtract 70 on both sides and you get -4q= 10
divide -4 on both sides and you get q= 10/-4 or -2.5
Answer:
10, 11, 12
Step-by-step explanation:
Hi there!
Let <em>x</em> be equal to the smallest integer.
Let <em>x</em>+1 and <em>x</em>+2 be equal to the consecutive integers.
We're given that:
⇒ smallest integer + 2 × middle integer = 20 + largest integer
Construct an equation:

Combine like terms:

Therefore, the smallest integer is 10.
This makes the consecutive integers 11 and 12.
I hope this helps!