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pav-90 [236]
3 years ago
7

1/3 + 5/6 + 5/12 What is the answer

Mathematics
2 answers:
AlladinOne [14]3 years ago
6 0
Set all of the denominators to 12 by multiplying 1/3 by 4/4, and 5/6 by 2/2. Now just add them together. 4/12+10/12+5/12=19/12. Or 1 and 7 twelves.
SOVA2 [1]3 years ago
3 0
1/3 + 5/6 + 5/12

1.583333333333333
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Tan(y)+ cot(y)/csc(y)= sec(y) prove identity
ArbitrLikvidat [17]

[tan(y) + cot (y)]/csc (y)

tan (y) = sin (y)/cos (y)
cot (y) = cos (y)/sin (y)
csc (y) = 1/sin (y).
Now rewrite the expression with the equivalent values

[sin (y)/cos (y) + cos (y)/sin (y) ] / [1/sin (y)]

1st, let's work the Numerator only = [sin (y)/cos (y) + cos (y)].
                  = [(cos² (y) + sin² (y)]/ [cos (y).sin(y)]

or (cos² (y) + sin² (y) = 1, →Numerator = 1/[cos (y).sin(y)]

Denominator = csc (y) = [1/sin (y)], Then:

N/D = 1/[cos (y).sin(y)] / [1/sin (y)] =  [1 x sin (y)]/ [cos (y).sin (y)] = 1/cos (y)

 Or 1/cos (y) = sec (y) Q.E.D 
4 0
4 years ago
Plz help fast thank u <br><br><br><br><br><br> 14
Vlad1618 [11]

Answer:

4/9

Step-by-step explanation:

4 Squares of 9 are shaded = 4/9

4 0
4 years ago
Read 2 more answers
There are white, and red boats in a marina. Two-thirds of the boats in the marina are white, 4/7 of the remaining boats are blue
Over [174]

Answer:

105 boats

Step-by-step explanation:

Let x be the total number of boats in the marina.

If Two-thirds of the boats in the marina are white.

Fraction of the remaining boat= 1-⅔ =⅓

4/7 of the remaining boats are blue.

4/7 of ⅓ are blue

4/7 X ⅓ = 4/21 are blue

Fraction of Red Boats =

1-(Proportion of white Boats +Proportion of Blue Boats)

= 1-(2/3+4/21)=1/7

If there are 15 red boats,

1/7 of the total boats =15

1/7 X x=15

x=15X7

x=105

There are 105 boats in total on the marina

8 0
3 years ago
A local service agency hires you to estimate the average annual income of all 700 families living in a four square block section
Digiron [165]

Answer:

The true estimate of  the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval below

   34854.3  <  \mu < 35 745.7

Step-by-step explanation:

From the question we are told that

    The  sample size is  n =  50  

    The sample mean is \= x = \$ 35300

     The population standard deviation is  \sigma =  \$ 1800

From the question we are told the confidence level is  92% , hence the level of significance is    

      \alpha = (100 - 92 ) \%

=>   \alpha = 0.08

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.751

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>   E = 1.751  *  \frac{1800 }{\sqrt{50} }

=>   E =  445.7

Generally 92% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=> 35 300 -445.7 <  \mu < 35 300 + 445.7

=> 34854.3  <  \mu < 35 745.7

So the true estimate of  the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval

3 0
3 years ago
mrs. escalante was riding a bicycle on a bike path after writing to in over 3 of a mile she discovered that she still needs to t
mash [69]
Writing?  any ways if 3 miles is 1/4 of the total path then there is 3/4 remaining and we know that 1/4 is 3 miles so how many times does one fit into the denominator(4) it fits 4 times so muptily 3 by4 and you have your answer(12)
5 0
3 years ago
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