Question

Someone help pleasee

Answer 1

Answer:

Step-by-step explanation:

g(x) = 3f(-2x)

     = 3*([-2x)² + (-2x) - 2)

    = 3 (4x² - 2x - 2)

   =   3 * (4x² - 4x  +2x - 2)        {Rewrite the middle term}

  = 3 *[ 4x(x - 1) + 2(x - 1)]

 = 3* [ (x -1) *(4x + 2)]

 = 3(x - 1)(4x + 2)

x - 1 = 0    ;   4x + 2 = 0

x = 1         ;      4x   = -2

                        x = $\dfrac{-2}{4}=\dfrac{-1}{2}$

Roots:   x = 1 , (-1/2)