The two longer sides of a right angle triangle are 16 and 22
let 22 be the hypotenuse (the longest side)
use Pythagoras Therom a²+b²=c²
in this question c=22 and b=16
to find the shortest side
22²-16²=a²
484-256=a²
228=a²
a=√(228)
a= 15.1
Answer:Im not gonna tell you it, but you will have to subtract I think.
Step-by-step explanation:
Month 6, work down below
months / students
0 30 45
1 36 48
2 42 51
3 45 54
4 51 57
5 57 60
6 63 63
Answer:
These two triangles are <em>similar triangles. </em>This means that their side lengths are proportional to each other.
Thus, making line segment EC equal to "x", and BC equal to "y" we can write:
8/y = 28/(10+y)
The next step is to get rid of the fractions, which can be done by cross multiplying.
So we have:
8(10+y) = 28(y)
After distribution and some simplification, you should get the value of y.
80+8y = 28y
80 = 20y
80/20 = 20y/20
4 = y
y = 4
Knowing that y = BC, and y = 4, it is clear that BC = 4.
Since BC = 4, one can use the Pythagorean Theorem to solve for segment EC.
Pythagorean Theorem: a^2 + b^2 = c^2, where a and b are the side lengths of a right triangle, and c is the hypotenuse (in other words the longest side)
In our case, a and b are 8 and 4 (the order doesn't really matter here).
So we have: 8^2 + 4^2 = c^2
64 + 16 = c^2
80 = c^2
c = sqrt 80
c = 4 sqrt 5
And we arrive at the answer- EC = 4 sqrt 5, making B the correct choice.
Hope this helps!
