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Shkiper50 [21]
3 years ago
8

Change each base 10 number to a binary by the division method 5

Mathematics
1 answer:
deff fn [24]3 years ago
6 0

Answer:

Step-by-step exA wall is 1200 sq ft.

A gallon of paint covers 200 sq ft.

Complete the conversion factor: 1 gallon / ? sq ftplanation:

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Which of the following choices best justifies the conclusion based on the given information?
Sindrei [870]
To abide by the mathematical order of operations in this equation you must distribute "a" into "b" and "c" by multiplying, which is the distributive property. So the answer would be C. Distributive
8 0
3 years ago
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A box contains a collection of triangular and square tiles. There are 2525 tiles in the box, containing 8484 edges total. How ma
AnnyKZ [126]
Let us consider the number of edges = x
we know that a triangle will have 3 edges and a square will have 4 edges. Using this details we can form an equation.
3x + 4x = 8484
7x = 8484
x = 8484/7
  = 1212
Then
Number of square tiles = 1212/4
                                     = 303
So there are 303 square tiles in the box. I hope the procedure is clear enough for your understanding. You can always use this method for solving similar problems.
                                                      
5 0
3 years ago
Given the equation:
Alisiya [41]

Answer:

x = 1 and x = \frac{-4}{5}

Step-by-step explanation:

In this equation, a=5, b=-1, c=-4.

Plug these into the quadratic formula:

x = \frac{1+\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}   and x = \frac{1-\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}

Now, simplify the equations:

x = \frac{1+\sqrt{81} }{10} = \frac{1+9}{10} = \frac{10}{10} = 1

and

x = \frac{1-\sqrt{81} }{10} = \frac{1-9}{10} = \frac{-8}{10} = \frac{-4}{5}

5 0
4 years ago
The perimeter of a certain sqaure is 12 inches. Find the area of the sqaure in square inches​
sineoko [7]

Answer:

144 in sq

Step-by-step explanation:

multiply 12 by 12

4 0
3 years ago
Read 2 more answers
Question 9 of 10
Nonamiya [84]
The answer is B. 0.02
1/2 (100)(h) = 1
h= 2/100
=h = 0.02
8 0
3 years ago
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