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Degger [83]
2 years ago
14

Please help if possible its important!!​

Mathematics
1 answer:
Otrada [13]2 years ago
7 0

Answer:

600 ft³

Step-by-step explanation:

Base area: B

Base is triangle

base = 12 ft and height = 5 ft

Area of triangle = B = \frac{1}{2}* \ base * \  height

                                 = \frac{1}{2}*12 * 5\\\\= 6 * 5\\\\= 30 \ ft^{2}

H = 20 ft

Volume = B * H

             = 30 * 20

             = 600 ft³

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Solve for x using the quadratic formula x^2-6x +9=0
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Answer:

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EXPLANATION:

plug in inputs and do a little simplifying we get

x = 6 ± √(36-36) all of that over 2

So we simplify and we get 6±sqrt(0) / 2

Then we get 6/2 = 3

x-0 = x+0

thats why there is only one answer

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3 years ago
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notsponge [240]

5). Radius = 6 km. Circumference = 12π km. Area = 36π km²

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2 years ago
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A triangle has sides of lengths 6 cm, 10 cm and 11 cm. An equilateral triangle has the same perimeter. What is the length of the
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Step-by-step explanation:

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3 years ago
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Which one is it? Plz help
Bezzdna [24]

Multiplication and division with the powers of ten

So, when multiply powers of ten, all you have to do add up the powers.

The reverse goes when you are dividing. You would subtract the powers.

9 x 10^7                    =>   3 x 10^3

The words " how many times as large as " indicates that we are going to divide the two, making it look like this:

\frac{(9)(10^{7}) }{(3)(10^{3}) }

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6 0
2 years ago
Raíz cuadrada de 864
marshall27 [118]

Raíz cuadrada de 864

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

The general equation of ellipse is given as, x2a2+y2b2=1 x 2 a 2 + y 2 b 2 = 1 , where, a is length of semi-major axis and b is length of semi-minor axis.

centro: (0,0)

focus : (0, -√28) , (0, √28)

eje conjugado = 2√3

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

de los focos podemos obtener que: √28

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b = √3

podemos utilizar la siguiente fórmula para obtener a:

si despejamos a en la ecuación obtenemos lo siguiente:

ahora podemos sustituir los valores:

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

si graficamos la hipérbola, queda como en el documento adjunto.

To learn more hipérbola

Visit : brainly.com/question/24223341

#SPJ9

8 0
1 year ago
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