Answer:
the answer is 30
Step-by-step explanation:
the mid-segment of a triangle is half of the side that is parallel to it
mid-segment MJ is parallel to line LK
LK is 60, half of 60 is 30
MJ is 30
Answer: Last Option
![4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=4x%5E5%5Csqrt%5B3%5D%7B3x%7D)
Step-by-step explanation:
To make the product of these expressions you must use the property of multiplication of roots:
![\sqrt[n]{x^m}*\sqrt[n]{x^b} = \sqrt[n]{x^{m+b}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%2A%5Csqrt%5Bn%5D%7Bx%5Eb%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%2Bb%7D%7D)
we also know that:
![\sqrt[3]{x^3} = x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20x)
So
![\sqrt[3]{16x^7}*\sqrt[3]{12x^9}\\\\\sqrt[3]{16x^3x^3x}*\sqrt[3]{12(x^3)^3}\\\\x^2\sqrt[3]{16x}*x^3\sqrt[3]{12}\\\\x^5\sqrt[3]{16x*12}\\\\x^5\sqrt[3]{2^4x*2^2*3}\\\\x^5\sqrt[3]{2^6x*3}\\\\4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16x%5E7%7D%2A%5Csqrt%5B3%5D%7B12x%5E9%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B16x%5E3x%5E3x%7D%2A%5Csqrt%5B3%5D%7B12%28x%5E3%29%5E3%7D%5C%5C%5C%5Cx%5E2%5Csqrt%5B3%5D%7B16x%7D%2Ax%5E3%5Csqrt%5B3%5D%7B12%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B16x%2A12%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B2%5E4x%2A2%5E2%2A3%7D%5C%5C%5C%5Cx%5E5%5Csqrt%5B3%5D%7B2%5E6x%2A3%7D%5C%5C%5C%5C4x%5E5%5Csqrt%5B3%5D%7B3x%7D)
<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:
y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5
The formula to be used in the proceeding steps is a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting, a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5) =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope
y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
The percent of change would be -33.3% which would then equal a 33.3% decrease (when decimal is rounded)
what I did was turn 1/4 and 1/2 into decimals to make it easier to solve
90% in a fraction is the same as 90/100 simplified, is 9/10.
Hope this helps
