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guajiro [1.7K]
2 years ago
11

Simplify 14a over 15 Plus 2a + 36 over 5​

Mathematics
1 answer:
Yuliya22 [10]2 years ago
5 0

Answer:

(20a+108)/15

Step-by-step explanation:

First find LCM of the denominators. U will find it to be 15

Then calculate the number like this.

[(14a)×1/15×1]+[(2a+36)×3/5]

[(14a/15)]+[(6a+108)/15

(14a+6a+108)/15

(20a+108)/15

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If Marie were to paint her living room alone, it would take 7 hours. Her sister Barbara could do the job in 8 hours. How many ho
Zielflug [23.3K]

Answer:

\sf\longmapsto \:  3.73 hours

Step-by-step explanation:

\sf\longmapsto \:  \frac{1}{7 } +  \frac{1}{8}

\sf\longmapsto \:  \frac{15}{56}

Now, Reciprocal–

\sf\longmapsto \:  \frac{56}{15}

\sf\longmapsto \:  3.73 hours

4 0
2 years ago
A patient is given a 100-milligram dosage of a drug that decays exponentially at a rate of 11% per hour. The doctor wants to kno
I am Lyosha [343]

Answer:

This is an example of exponential decay (somewhat similar to half-life).

If it decays at 11% per hour we can calculate its half-life by this formula:

half life = [ time • ln (2) ] ÷ ln (beginning amount ÷ ending amount)

where "ln" means natural log

half life =[ 1 hour * .69315] / ln (100 / 89)

half life =[.69315] / ln (1.1235955056)

half life =[.69315] / 0.11653381624

half life = 5.9481 hours


We need "lambda" "λ" (the decay constant) which equals

λ  = ln(2) / half-life = .693147 / 5.9481 = 0.1165325062


Now we need a formula for the time required:

time = ln (Nt ÷ N0) ÷ -λ where No = beginning amount (100 milligrams) Nt = ending amount (15 milligrams)

time = ln (15 ÷ 100) ÷ -0.1165325062

time = ln (.15)  /  -0.1165325062

time = -1.8971199849 / -0.1165325062


time = 16.2797492885 hours

Source: https://www.1728.org/halflif2.htm



Step-by-step explanation:


4 0
2 years ago
Suppose that the functions g and f are defined as follows.
Sholpan [36]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Given:

\to g(x)= -3+2x^2 \\\\\to f(x)=9-6x

Calculating the value of (\frac{g}{f})(2):

\to (\frac{g}{f}) (2)= (\frac{g(x)}{f(x)}) \times  (2)

               =\frac{2x^2-3}{9-6x} \times 2\\\\=\frac{2\cdot 2^2-3}{3(3-2\cdot 2)} \\\\=\frac{2\cdot 4-3}{3(-1)}\\\\ =\frac{8-3}{-3}\\\\  =\frac{5}{-3}\\\\  = - \frac{5}{3}\\\\

x=- \frac{\sqrt{3}}{2} and x=\frac{\sqrt{3}}{2} are not in the domain.

Domain: x \belong (- \infty, -\frac{\sqrt{3}}{2})\cup (- \frac{\sqrt{3}}{2},  \frac{\sqrt{3}}{2} )\cup (\frac{\sqrt{3}}{2}, \infty)

8 0
3 years ago
The price of gasoline is $3.15 the price when Ryan's mother start drawing was 4/7 of the current price what was the price of the
zlopas [31]

Answer:

$3

Step-by-step explanation:

5 0
3 years ago
If a school bought 3 cheese pizzas and 1 pepperoni pizza how many cheese and pepperonis pizzas did they get if they bought 6 che
oksian1 [2.3K]

\text{Hello there!}\\\\\text{Turn this into a ratio:}\\\\\text{For everyone 3 cheese pizzas, they get 1 pepperoni pizza}\\\\\text{The ratio would be 3:1}\\\\\text{We need to find how many pepperoni pizzas they got if they bought 6}\\\text{cheese pizzas}\\\\\text{3 times 2 makes 6, so multiply 1 times to get your answer}\\\\\text{The ratio would be 6:2}\\\\\boxed{\text{2 pepperoni pizzas (8 pizzas in total)}}

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2 years ago
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