Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
<h3>
Answer: K ' is at (1, 4)</h3>
Explanation:
Point K is located at (1, -4)
We use the rule that 
when reflecting over the x axis.
The x coordinate stays the same, but the y coordinate flips from positive to negative or vice versa.
Therefore, K(1,-4) will move to K ' (1, 4)
Answer:
16
Step-by-step explanation:
Answer:24
xexponet
3
−
5
Step-by-step explanation:
Answer:
18/44
Step-by-step explanation:
To turn 9/22 into something over 44, we need to figure out what to multiply it by.
44 / 22 = 2.
Multiply 9/22 by 2:
9/22 * 2 = 18/44
