a = amount invested at 13%
b = amount invested at 2%
we know the total amount invested is 8200, so if the first amount is say "a", the second amount must be the slack left from subtracting "a", namely b = 8200 - a.
we also know 13% of "a" plus 2% of "b" yielded an interest of $461 in a year.
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{13\% of a}}{\left( \cfrac{13}{100}\right)a\implies 0.13a}~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)b\implies 0.02b} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B13%5C%25%20of%20a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B13%7D%7B100%7D%5Cright%29a%5Cimplies%200.13a%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B2%5C%25%20of%20b%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B2%7D%7B100%7D%20%5Cright%29b%5Cimplies%200.02b%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \stackrel{\textit{sum of the percentages}}{0.13a+0.02b}~~=~~\stackrel{\textit{yield for 1 year}}{461}\implies 0.13a+0.02\left(\boxed{8200-a} \right) = 461 \\\\\\ 0.13a+164-0.02a=461\implies 0.11a+164=461\implies 0.11a=297 \\\\\\ a = \cfrac{297}{0.11}\implies \blacktriangleright a = 2700 \blacktriangleleft ~\hfill b = 8200-2700\implies \blacktriangleright b = 5500 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20the%20percentages%7D%7D%7B0.13a%2B0.02b%7D~~%3D~~%5Cstackrel%7B%5Ctextit%7Byield%20for%201%20year%7D%7D%7B461%7D%5Cimplies%200.13a%2B0.02%5Cleft%28%5Cboxed%7B8200-a%7D%20%5Cright%29%20%3D%20461%20%5C%5C%5C%5C%5C%5C%200.13a%2B164-0.02a%3D461%5Cimplies%200.11a%2B164%3D461%5Cimplies%200.11a%3D297%20%5C%5C%5C%5C%5C%5C%20a%20%3D%20%5Ccfrac%7B297%7D%7B0.11%7D%5Cimplies%20%5Cblacktriangleright%20a%20%3D%202700%20%5Cblacktriangleleft%20~%5Chfill%20b%20%3D%208200-2700%5Cimplies%20%5Cblacktriangleright%20b%20%3D%205500%20%5Cblacktriangleleft)
Answer: There are 1.52 pints in 720 mililiters.
Step-by-step explanation:
You need to remember that there are 473.176 mililiters in 1 pint.
Therefore, having 720 mililiters, you need to make the corresponding conversion from mililiters to pints.
Then, you get that 720 mililiters to pints is:
![=(720mililiters)(\frac{1pint}{473.176mililiters})\\\\=1.52pints](https://tex.z-dn.net/?f=%3D%28720mililiters%29%28%5Cfrac%7B1pint%7D%7B473.176mililiters%7D%29%5C%5C%5C%5C%3D1.52pints)
Therefore, the answers is: There are 1.52 pints in 720 mililiters.
The graph is shown below.