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Andrei [34K]
3 years ago
5

What would be the answer to both?

Mathematics
1 answer:
dezoksy [38]3 years ago
6 0

Answer:

f(- 3) = 51, g(2) = - 11

Step-by-step explanation:

To evaluate f(- 3), substitute x = - 3 into f(x), that is

f(- 3) = - 2(- 3)³ - 3 = - 2(- 27) - 3 =  54 - 3 = 51

Similarly for g(2)

g(2) = - 5(2) - 1 = - 10 - 1 = - 11

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Help me :( please help me
Katena32 [7]

Answer:

22.84, 5.83

Step-by-step explanation:

Pythagoras theorem states that: a^2+b^2=c^2

So, for red triangle, it will be: 9^2+21^2=b^2

81+441=b^2

522=b^2

square root of 522=b

22.84=b

For purple one,

3^2+5^2=a^2

9+25=a^2

34=a^2

square root of 34=a

5.83=a

7 0
2 years ago
Alex has 520 yards of fencing to enclose a rectangular area.
Pavlova-9 [17]
<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.

p=2w+2w=520=4w
w=130

Area
 
A=wL=130(130)= 16900 square yards</span>
6 0
3 years ago
Read 2 more answers
A rectangular prism has a width of 51 ft and a volume of 144 ft3. Find the volume of a similar prism with a width of 17 ft. Roun
meriva

Answer:

5.3\ ft^3

Step-by-step explanation:

Similar shapes with scale factor k have proportional volumes with coefficient k^3 i.e.

\dfrac{V_{large}}{V_{small}}=k^3,

where

k=\dfrac{\text{width of large prism}}{\text{width of small prism}}.

Since

\text{width of large prism}=51\ ft,\\ \\\text{width of small prism}=17\ ft,

then

k=\dfrac{51}{17}=3.

Hence,

\dfrac{144}{V_{small}}=3^3\Rightarrow V_{small}=\dfrac{144}{27}=\dfrac{16}{3}=5\dfrac{1}{3}\approx 5.3\ ft^3.

7 0
3 years ago
An exercise machine with an original selling price of $1275 is marked down by 20% . What is the sale price of the exercise​ mach
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Answer: The machine would now be $1020
Step-by-step explanation: Multiply $1,275 by 0.8 because 0.8 is 20% off, then you get your answer.
8 0
3 years ago
Read 2 more answers
You deposit $500 into an account that pays 4.25% annual interest compounded continuously. What is the balance after 10 years?
scZoUnD [109]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$500\\ r=rate\to 4.25\%\to \frac{4.25}{100}\dotfill &0.0425\\ t=years\dotfill &10 \end{cases} \\\\\\ A=500e^{0.0425\cdot 10}\implies A=500e^{0.425}\implies A\approx 764.80

6 0
2 years ago
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